Let flat rental fee be F
And per mile charge be M
We know that Bob drove 138 miles and was charged $112.96
And Carl drove 209 miles and was charged $142.78.
⇒ F + 138×M = 112.96 .............. (i)
And F + 209×M = 142.78 ................ (ii)
Subtracting (i) from (ii)
71×M = 29.82
⇒ M = 0.42
Substituting value of M in (i)
⇒ F + 138×0.42 = 112.96
⇒ F + 57.96 = 112.96
⇒ F = 55
So the fixed charge was $55 and the per mile charge was $0.42
Answer:
Step-by-step explanation:
I have attached the steps so good luck
Answer:
3.9 mi/h
Step-by-step explanation:
We assume that the given speeds are the speeds of the boats relative to the water. If c is the speed of the current, we have ...
time = distance/speed
47/(15 +c) = 40/(20 -c)
47(20 -c) = 40(15 +c) . . . . . . multiply by (20-c)(15+c)
940 -600 = 40c +47c . . . . . add 47c-600
340 = 87c . . . . . . . . . . . . . . . simplify; next divide by 87
c = 340/87 ≈ 3.9080 . . . . mi/h
The speed of the current is about 3.9 mi/h.
