Question

In a 3-digit number, the hundreds digit is four more than the ones digit and the tens digit is twice the hundreds digit. If the sum of the digits is 12, find the three digits. Find the number.
If the with of the rectangle is x, then the equation is...

Answer 1

First of all, we know that the number has 3 digit, so we have this expression;
a00+b0+c where a00 represent hundreds, b0 represent tens, and c represent one
Or you can just have this abc instead of a00+b0+c
Next step:
the hundreds digit is four more than the ones digit. Translate this into the number which is:
a=4+c, or c=a-4
the tens digit is twice the hundreds digit, and translate this too which is:
b=2a
Lasly,
The sum of the digits is 12, also translate this:
a+b+c=12
c=a-4
b=2a
Substitute all this into a+b+c=12
a+2a+a-4=12
4a-4=12
Add 4 to each side
4a-4+4=12+4
4a=16
Divided 4 to both side
4a/4=16/4
a=4
b=2a
b=2(4)
b=8
c=a-4
c=4-4
c=0. As a result, the three digit is 480 which is your final answer. Hope it help!

Answer 2

480. And I don't understand the bottom part