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yan [13]
4 years ago
13

Use the graph of the function f to determine f(x)

Mathematics
1 answer:
Fed [463]4 years ago
6 0

Answer: option a.

Step-by-step explanation:

The \lim_{x \to a} f(x) give us information about the behavior of the function when the variable <em>x </em>gets closer to the value <em>a. </em>In other words, it tells us to what value <em>y</em> gets closer when <em>x </em>gets closer to the value <em>a. </em>

<em> </em>In this case we are evaluating the limits when:

{x \to -3}

{x \to 0}

{x \to 2}

of the function shown in the graph.

As you can observe in the graph, when:

{x \to -3} , y=3

{x \to 0} , y=0

{x \to 2} , y=-2

You might be interested in
Two is equal to 4 less than 3 times a certain number. Find the number.
Allushta [10]

Answer:

2

Step-by-step explanation:

2=3x-4

6=3x

x=2

5 0
3 years ago
Read 2 more answers
Please help me please I need help!!!!!!!!!!!!!!!!!!!hshdjdndndbdbnfjfkfkfkdkdkfkfjdjfiid
Serggg [28]

y = (x - 2)(x + 5)    First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

y = x² + 3x - 10


Next I would plug in a number for x to find its y value. I will plug in 0

y = 0² + 3(0) - 10

y = -10

(0, -10)   [this is the y-intercept (the y value when x = 0)]


Your answer is Graph A because the y-intercept is (0,-10)

6 0
4 years ago
What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
!!ASAP!! !!HELP!!<br> pls help. iv been trying to do this for 3 days. please.
Jet001 [13]

Answer:

Three equivalent expressions are -3(5-2x), 6x-15, and 3(2x-5).

Step-by-step explanation:

They are equivalent because they equal the same value for x and make the same answer.

6 0
2 years ago
MULTIPLE CHOICE
loris [4]

Answer:

18.18 mph

Step-by-step explanation:

6 0
3 years ago
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