Answer:
2nd row, circle is <u><em>6</em><em>x</em><em> </em><em>+</em><em> </em><em>2</em><em>y</em></u><em>.</em>
3rd row, rectangle is <u><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>y</em></u><em> </em>and circle is <u><em>5</em><em>x</em></u><em>.</em>
Step-by-step explanation:
As the question say when 2 rectangles, at the sides are add up together, it will form circle in the middle. So in order to find circle or rectangle, you either have to add or substract :
For 2nd row, circle,
T/L(r) + B/R(r) = M(c)
4x + 3y + 2x - y = M(c)
6x + 2y = M(c)
M(c) = 6x + 2y
For 3rd row, rectangle,
T/L(r) + B/R(r) = M(c)
x + 4y + B(r) = 4x + 5y
B(r) = 4x + 5y - x - 4y
= 3x + y
For 3rd row, circle,
T/L(r) + B/R(r) = M(c)
2x - y + 3x + y = M(c)
5x = M(c)
M(c) = 5x
* Take note, for 3rd row, you first have to find the rectangle then circle.
Symbols :
- T/L(r) = Top/Left (rectangle)
- B/R(r) = Bottom/Right (rectangle)
- M(c) = Middle (circle)
Answer: T(90) = 93.413 F
Step-by-step explanation:
The temperature T of an object in degrees Fahrenheit after t minutes is represented by the equation
T(t) = 69e−0.0174t + 79.
T is the dependent variable while t is the independent variable. To determine any value for Temperature, we will input the corresponding value for time into the function.
We want to determine the temperature of the object after one and a half hours. This means that we have to convert one and a half hours to minutes
1f 1 hour = 60 minutes
Then 1.5 hours = 1.5 × 60 = 90 minutes.
We would substitute t = 90 minutes into the equation, it becomes
T(90) = 69e−0.0174×90 + 79
T(90) = 69e−1.566 + 79
T(90) = 14.413 + 79
T(90) = 93.413 F
Answer:
n - 8 >= 10
n minus 8 is greater than or equal to 10
Answer:
i what are u learning-
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The black graph is the graph of y=f(x).
The red graph is the reflection of the black graph across the y-axis.
A.
determines the translation of the graph
one unit to the right.
B.
determines the reflection of the graph
across the y-axis.
C.
determines the translation of the graph
one unit up.
D.
determines the reflection of the graph
across the y-axis.