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OLga [1]
3 years ago
11

Can someone help me with this 9/10 ÷2/5

Mathematics
2 answers:
RUDIKE [14]3 years ago
5 0
9/10 ÷ 2/5 = 9/10 x 5/2 = 9/2 x 1/2 = 9/4
Juliette [100K]3 years ago
5 0
9/10 ÷ 2/5 =
= 9/10 × 5/2 (We use reciprocals when dividing fractions - flip the second element)
= 45/20 =
= 2.25 or 9/4 or 2 1/4
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Given that (-4,2) is on the graph of f(x) find the corresponding point for the function -1/2f(x)
Aleks [24]

Answer:

The corresponding point is (-4.-1)

Step-by-step explanation:

we know that

The point (-4,2) is on the graph of f(x)

so

For x=-4

f(x)=2

therefore

For x=-4

-(1/2)f(x)=-(1/2)*2=-1

The corresponding point is (-4.-1)

8 0
3 years ago
Match the vocabulary word with the correct definition. 1. inverse operations terms that have the same variable(s), with each var
Licemer1 [7]

Answer:

inverse operations is with oppisite operations that undo each other.

open circle is circle not filled in to show that the point is a border value and is not included as part of the solution set.  

like terms is terms that have the same varible raised to the same exponent.

ordered pair is a group of two numbers written in the form (x, y) where the x value represents a horizontal position.

the last one numeric expressions is an expression involving only constants

Step-by-step explanation:

7 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
Which of the following is the inverse of y = 3 Superscript x?
Alina [70]

Answer:

- f−1=log3x. Explanation: y=3x ⇒log3y=log3(3x) (logarithms of both side are equal) ⇒x=log3y ⇒f−1=log3x.Step-by-step explanation:

4 0
4 years ago
Can someone help me with this problem please h + 11/12 = 120 1/2
ira [324]

Your answer would be h=1435/12

8 0
3 years ago
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