Ask question

Ask question

All categories

3 years ago

11

The state of Colorado is in the shape of a rectangle whose length is 380 miles and whose length is 380 miles and whose width is

280 miles. Find its area. how do I work this out

2 answers:

KiRa [710]3 years ago

8 0

Area of a rectangle is Length times width
So basically 380 * 280 should be the answer
The answer should be 106400

balandron [24]3 years ago

3 0

Area= l x w

380 x 280= 106400 miles

hope this helps

You might be interested in

Find the LCM of 6 and 8.<br><br> A) 12 <br> B) 18 <br> C) 24 <br> D) 36

frez [133]

Answer:

The answer is C) 24

3 0

2 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0

3 years ago

California's highest point, Mt. Whitney, stands 14,505 ft. above sea level. California's lowest point, Death Valley, is 282 ft.

Ainat [17]

Answer:

Difference is 14,787 ft

Step-by-step explanation:

Mt. Whitney = 14,505 ft above sea level

sea level = 0 ft

Death Valley = below sea leve

14505 - (-282) = 14787 ft

4 0

2 years ago

Can someone help me with this please & explain how to find the answer?

nikitadnepr [17]

Answer:

the answer is the first one

Step-by-step explanation:

because when you look at the order <MNK is on the other side to the line that bisects the two parallel lines of <LKN

5 0

3 years ago

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

3 years ago