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3 years ago

What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?

Mathematics

2 answers:

NeX [460]3 years ago

8 0

Answer:

the newsar si evsenyt esventy

Step-by-step explanation:

9966 [12]3 years ago

6 0

Answer:

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

Step-by-step explanation:

For n=6 the degrees of freedom will be n-1 = 5 .

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

The critical region depends on ∝ and the alternative hypothesis

a) When Ha is σ²≠σ² the critical region is

χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test

( χ² < 0.83) and ( χ² > 0.83)

b) When Ha is σ²> σ² the critical region falls in the right tail and its value is

χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}

c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value

χ²(1-∝)(n-1) One tailed test (1.145)

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3 years ago

According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A rando

Nimfa-mama [501]

Answer: No, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

Step-by-step explanation:

Since we have given that

n = 1400

x = 154

So, $\hat{p}=\dfrac{154}{1400}=0.11$

and p = 0.10

So, hypothesis would be

$H_0:\hat{p}=p\\\\H_a:\hat{p}>p$

So, the test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.11-0.10}{\sqrt{\dfrac{0.1\times 0.9}{1400}}}\\\\z=\dfrac{0.01}{0.008}\\\\z=1.25$

At 5% level of significance,

critical value would be 1.96.

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Hence, no, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

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3 years ago

Sequence: 49, 36, 25, 16, 8, 4, 1 * Is this a arithmetic or geometric sequence? and if it is arithmetic find the common differen

timurjin [86]

Answer:

Step-by-step explanation:

The sequence is nor properly written. This is correct sequence

49, 36, 25, 16, 9, 4, 1...

Merely looking at the sequence, we can see that it doesn't form an arithmetic sequence nor does it form a geometric sequence.

The values of the sequence are all perfect squares.

Rewriting the sequence;

7², 6², 5², 4², 3², 2², 1²...

Now we can see that the base values for an arithmetic sequence as shown:

7, 6, 5, 4, 3, 2, 1...

We find the common difference of this sequence as shown

d = T2-T1 = T3-T2 = T4-T3

Given T1 = 7, T2 = 6, T3 = 5, T4 = 4

Substitute

d = 6-7 = 5-6 = 4-5 = -1

d = -1

Get the nth term using the sequence

Tn = a+(n-1)d

a is the first term

d is the common difference

n is number of terms

Tn = 7+(n-1)(-1)

Tn = 7+(-n+1)

Tn = 7+1-n

Tn = 8-n

Since their power are constant i.e squared, hence we will square the ntj term as well to get the nth term of the original sequence as;

Tn = (8-n)²

To conclude, we can say that the sequence is neither arithmetic nor geometric sequence since the terms of the sequence are prefect squares.

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Answer:

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