Answer:
Straight-line equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them. If you see an equation with only x and y – as opposed to, say x2 or sqrt(y) – then you're dealing with a straight-line equation.
There are different types of "standard" formats for straight lines; the particular "standard" format your book refers to may differ from that used in some other books. (There is, ironically, no standard definition of "standard form".)
Hey there Hailey!
So, to start this all of, what formula are we even going to use.
The formula that we will be using in this question would be
. . .
![\left[\begin{array}{ccc}\boxed{V= \pi r^2 \frac{h}{2}} \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7BV%3D%20%5Cpi%20r%5E2%20%5Cfrac%7Bh%7D%7B2%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%20)
So, now that we know what formula that we will use, we will now plug in those number's
the formula.
Justification:
We do,
![\left[\begin{array}{ccc}27*3.14= \boxed{84.78} \\ Your \ correct \ answer \ would \ be \ \boxed{\boxed{27}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D27%2A3.14%3D%20%5Cboxed%7B84.78%7D%20%5C%5C%20Your%20%5C%20correct%20%5C%20answer%20%5C%20would%20%5C%20be%20%5C%20%5Cboxed%7B%5Cboxed%7B27%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps you!
~Jurgen
We try to represent each number inside the square root as a product of a square and another number.
a) 7√32 - 5√2 + √8
√32 = √(16 *2) = √16 * √2 = 4* √2 = 4√2
√8 = √(4 *2) = √4 * √2 = 2* √2 = 2√2
7√32 - 5√2 + √8 = 7*(4√2) - 5√2 + 2√2 =
= 28√2 - 5√2 + 2√2 Factorize out √2
= (28 - 5 + 2)√2
= 25√2
b) 2√150 - 4√54 + 6√24
√150 = √(25 * 6) = √25 * √6 = 5*√6 = 5√6
√54 = √(9 * 6) = √9 * √6 = 3*√6 = 3√6
√24 = √(4 * 6) = √4 * √6 = 2*√6 = 2√6
2√150 - 4√54 + 6√24 = 2*(5√6) - 4*(3√6) + 6*(2√6)
= 2*5√6 - 4*3√6 + 6*2√6
= 10√6 - 12√6 + 12√6 Factorize √6
= (10 - 12 + 12)√6
= 10√6
Answer:
Dunno
Step-by-step explanation:
Sorry :/
A - 2 1/2 = 1 1/2
Solve for A by adding 2 1/2 to both sides:
A = 1 1/2 + 2 1/2
A = 4
The answer is c. A = 4
Check: 4 - 2 1/2 = 1 1/2
