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zaharov [31]
3 years ago
13

I need help with both questions, you can answer either exercise #2 or #4 or both if you want to.

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0
For 2a, we plug 3 in to get (4*3+3)/(3^2-7)=15/2. Since 2 is a prime number and 15 is not divisible by 2, this is simplest form. For b, using PEMDAS, division goes before addition or subtraction and 3/3^3 would therefore be done and you could not add 4*3 beforehand (or subtract 7).

For 4a, we plug it in to get sqrt(25-(-3)^2)=sqrt(25-9)=sqrt(16)=4

For b, since 13^2=169 and 25-169 is negative, we cannot find the square root due to that nothing squared is negative.
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Complete the following statements. In general, % of the values in a data set lie at or below the median. % of the values in a da
ELEN [110]

Answer:

Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).

Step-by-step explanation:

The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.

The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.

The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.

The answer is:

Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).

5 0
2 years ago
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3 years ago
What is ∛1728. Then multiplied by ∛14903
NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate \sqrt[3]{1728} and then multiply the result by \sqrt[3]{14903}

Let us first evaluate \sqrt[3]{1728}

\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12

As need to multiply 12 by \sqrt[3]{14903}

\Rightarrow 12 \times \sqrt[3]{14903}

On solving \sqrt[3]{14903}, we get

\sqrt[3]{14903}=24.608

\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306

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