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Arlecino [84]
3 years ago
6

How do you find the square root of 50?

Mathematics
1 answer:
slega [8]3 years ago
7 0
Find the nearest numbers that are greater and less that your number, in this case, 7 and 8 which square to 49 and 64 and average them by adding them together and dividing by two.
7+8=15
15/2=7.5
7.5 is the nearest estimated square root of 50 that I can get, but the real answer is about 7.071067811865475. (I used a calculator)
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A triangle has vertices at (4,3), (-2,4), and (-4, 2). What are the coordinates of the vertices of the image
Alexeev081 [22]

The coordinates are (4,3) ►(6,-2)

(-4,2) ►(-2,-3)

. (-2,4) →(0,-1)

8 0
3 years ago
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All of the edges of a regular triangular pyramid have length 12. A frustum of the pyramid has height half of that of the pyramid
vlada-n [284]

Answer:

1) The volume of the frustum is 27·(√3)·h

2) The surface area the frustum is 24·h + 54·√3

Step-by-step explanation:

1) A frustum of the regular triangular prism is a portion of the triangular prism

The length of the edge of the triangle prism = 12

The area of the triangular face, A = (√3/4)·a²

∴ A = (√3/4)·12² = 36·√3

When

The volume of the triangular prism, V = A·h = (36·√3)·h

By triangle proportionality theorem, the cross sectional area of the top half of the triangular prism =  (√3/4)·6² = 9·(√3)

The volume of the top half, V₂ = 9·(√3)·h

The volume of the frustum = V - V₂ = (36·√3)·h - 9·(√3)·h = 27·(√3)·h

The volume of the frustum = 27·(√3)·h

2) The surface area of the triangular side of the frustum is given as follows;

A = 36·√3- 9·(√3) = 27·(√3)

The surface area the frustum, F_A = 2×27·(√3) + 2 ×6 ×h + 12×h = 24·h + 54·√3

The surface area the frustum = 24·h + 54·√3

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The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?
Lena [83]
He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix? 
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
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<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
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<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
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<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
8 0
4 years ago
Read 2 more answers
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