Answer:
Step-by-step explanation:
This problem is all about bases and exponents. Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:
That's the simplification as long as you are "allowed" to leave the exponent as a negative number.
Answer:
bus = 43
van 12
Step-by-step explanation:
This can be solved using simultaneous equations
Let v represent the number of students that a van carries
Let b represent the number of students that a bus carries
the following equations can be derived from the question
3v + 2b = 122 eqn 1
5v + 3b = 189 eqn 2
Multiply eqn 1 by 5 and eqn 2 by 3
15v + 10b = 610 eqn 3
15v + 9b = 567 eqn 4
Subtract equation 4 from 3
b = 43
Substitute for b in equation 1
3v + 2(43) = 122
solve for v
v = 12
Answer:
-10
Step-by-step explanation:
After I looked up some quick information, your car loses 15-25% each year. After 5 years, it goes to only 37%. So, a car that would cost 20000 would be valued at around 7k after 5 years. So, in the first 5 years, it lost 14k. Also, a 1999 Corolla goes for 2.5k, and that's nearly 20 years. So, I'm just going to go with, based off these numbers, probably 25-30 years...if it still works by then.
Also, if you get in a heavy accident the next day, making the car unusable, you rip off your friend. The first scenario only applies if the engine works well and no accidents were on the vehicle either.
