2.45kg

First you calculate the price per kg as follows:

If it’s $20 for 12.25 kg, the price per kg is $20/12.25=$1.63 per kg

If you have $4, you can figure out what weight you can get by taking $4/the price per kg, so $4/$1.63, which is 2.45 kg.

4 0

3 years ago

What’s the correct answer for this question?

aksik [14]

Answer:

Step-by-step explanation:

Density = Mass/ Volume

2 = 8 / V

V = 8/2

V = 4 cubic cm

3 0

3 years ago

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If the perimeter of a square is 5 feet now many Inches long is each side of the square

gogolik [260]

Answer:

Well since we know that the perimeter of a square is four times the length of one of its sides. We just have to divide 5 by 4 to get the length of one side:

5feet /4 sides = 1.25 feet

And to finish off, we have to convert feet to inches:

1 foot = 12 inches

1.25 feet x inches

x inches = 12 inches x 1.25 feet ÷ 1 foot

x inches = 15 inches

Therefore, each side is 15 inches long.

Hope this helps!

Step-by-step explanation:

7 0

3 years ago

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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago