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Alenkinab [10]
3 years ago
5

Factor the quadratic expression completely. 12x^2+17x+6=

Mathematics
1 answer:
motikmotik3 years ago
6 0

Answer:

(3 x + 2) (4 x + 3)

Step-by-step explanation:

Factor the following:

12 x^2 + 17 x + 6

Factor the quadratic 12 x^2 + 17 x + 6. The coefficient of x^2 is 12 and the constant term is 6. The product of 12 and 6 is 72. The factors of 72 which sum to 17 are 8 and 9. So 12 x^2 + 17 x + 6 = 12 x^2 + 9 x + 8 x + 6 = 3 (3 x + 2) + 4 x (3 x + 2):

3 (3 x + 2) + 4 x (3 x + 2)

Factor 3 x + 2 from 3 (3 x + 2) + 4 x (3 x + 2):

Answer:  (3 x + 2) (4 x + 3)

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Find the absolute maximum and absolute minimum values, if any, of the function. (If an answer does not exist, enter DNE.)f(x) =
lyudmila [28]

Answer:

The absolute minimum value is "-\frac{21}{4}" and the absolute maximum value is "15".

Step-by-step explanation:

Given:

f(x)=x^2-x-5

on,

[0,5]

By differentiating it, we get

⇒ f'(x)=2x-1

Set f'(x)=0

then,

⇒ 2x-1=0

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When x=0,

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When x=\frac{1}{2},

⇒ f(x)=-\frac{21}{4} (Absolute minimum)

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7 0
3 years ago
What is the square root of y^3
tia_tia [17]

Answer:

y^{\frac{3}{2}

Step-by-step explanation:

Let m=\sqrt{y^3}

m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}

7 0
3 years ago
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Olegator [25]

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y=mx+b

Step-by-step explanation:

that is the equation

4 0
3 years ago
Multiply.
horrorfan [7]

Answer:

The answer is 6

Step-by-step explanation:

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8 0
3 years ago
The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba
sergiy2304 [10]

THE ANSWER IS A:

This is the function:

f(x)=|42.67-x|.

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42.668 mm to 42.670

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Production will be stopped if the difference in diameter is greater than 0.002 mm.

This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.

 Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.

4 0
3 years ago
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