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pshichka [43]
3 years ago
13

Find x - y less than 0.

Mathematics
1 answer:
shutvik [7]3 years ago
4 0
Is there any choices if not it could be 1 - 2 or abouve the first nuber x has to be smaller and y has to be bigger
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Does anyone know what this is?
harkovskaia [24]

Answer:

its either 3.111111

or 27+1

       9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Simplify. <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8m%7D%20%7B%7D%5E%7B3%7D%20" id="TexFormula1" title=" \sqrt[
olya-2409 [2.1K]

\sqrt[3]{8m}^3

  • Set up

(8m^{\frac{1}{3}})^3

  • Convert the radical into a fractional exponent using \sqrt[n]{x^m} = x^{\frac{m}{n}}

8m^{(3 \cdot \frac{1}{3})}

  • Use the property that (x^a)^b = x^{(a \cdot b)}

8m

  • Simplify

The simplification would be 8m.



7 0
3 years ago
Decide if the statement is giving you the x or y value of the function
const2013 [10]

Answer: 1a. f(2) is an x-value

1b. f(x) = 4 is a y-value

1c. f(-10) is an x-value

1d. m(x) = 64 is a y-value

2.  f(4) = 17

3.  x = 39

Step-by-step explanation:  In general, if there is an equal sign, the output f(x) is a y-value. if the expression is f(#) with a number in the parentheses, that is the value to insert for x.

2.) f(x) = 2x + 9

f(4) = 2(4) + 9

f(4) = 8 + 9

f(4) = 17

3. f(x) = 5x -3

192 = 5x -3

192 + 3 = 5x

195 = 5x

39 = x

5 0
2 years ago
Which of the
Nadya [2.5K]

Answer:

c?

Step-by-step explanation:

8 0
3 years ago
If the parabola of the form y = a(x – h)2 + k is always shifted horizontally h units and vertically k units, then its vertex is
STatiana [176]

The vertex of the transformed parabola with the equation y=a(x-h)^2+k is (h, k).

<h3>What are the transformation rules for horizontal and vertical shifts?</h3>

The transformation rules are:

Translation: (x, y) → (x + a, y) or (x, y) → (x - a, y) (Horizontal shift)

Translation: (x, y) → (x , y + b) or (x, y) → (x , y - b) (Vertical shift)

<h3>Calculation:</h3>

It is given that, the transformed parabola is y=a(x-h)^2+k

This parabola has vertex at (h, k).

Since this equation is obtained by shifting h units horizontally and k units vertically.

So, the original vertex is at (h - h, k - k) = (0, 0)

Thus, the equation of the actual parabola is y=ax^2

Therefore, the given transformed equation of parabola has vertex (h, k).

Learn more about transformation rules here:

brainly.com/question/12537916

#SPJ1

3 0
2 years ago
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