R = 5n + 5w
r - 5w = 5n
r/5 - w = n
Answer:
168 km
Step-by-step explanation:
Let x represent the distance Tyler drives at the slower speed, and let y represent the distance at the higher speed. Using time = distance/speed, we can write equations for the total travel time:
x/42 +y/105 = 2.5
x/28 +y/60 = 4.0 . . . . . 1.5 hours more than the usual 2.5 hours
Multiplying the first equation by 210, we have ...
5x +2y = 525
Multiplying the second equation by 420, we get ...
15x +7y = 1680
Subtracting 3 times the first of these equations from the second, we have ...
(15x +7y) -3(5x +2y) = (1680) -3(525)
y = 105
Putting this into the very first equation, we get ...
x/42 + 105/105 = 2.5
x/42 = 1.5 . . . . . . subtract 1
x = 63 . . . . . . . . .multiply by 42.
The total distance to Tyler's parents' house is ...
63 km + 105 km = 168 km
The answer is B The domain is all real numbers such that ...
Question 1:
To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.
A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram.
A square has 4 right angles, so it's also a rectangle.
A square has 4 sides, so it's also a quadrilateral.
The first choice is your answer.
Question 2:
Not all quadrilaterals are rectangles, so A is incorrect.
Not all quadrilaterals are squares, so B is incorrect.
All rectangles are types of quadrilaterals, so C is correct.
Not all quadrilaterals are parallelograms, so D is incorrect.
Thus, C is your answer.
Question 3:
The first choice will not work because a rhombus will satisfy those conditions, and a rhombus is not always a square.
The second choice will work because only a square will satisfy that condition because only squares have 4 congruent sides along with equal diagonals.
Thus, the second choice is your answer.
Have an awesome day! :)
Answer:
The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
Step-by-step explanation:
We are given 
We need to solve for x
First we subtract 2 both sides
Taking cube roots both sides to isolate x
![x=\sqrt[3]{16}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B16%7D)
Simplify the radical
![x=2\sqrt[3]{2}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B2%7D)
Thus, The value of x is
