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3 years ago

What is the volume of the figure?

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

4 0

Answer:

47.12

Step-by-step explanation:

same as the last question

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What is 6.699 rounded to the nearest whole number

gregori [183]

The correct answer would be 7! Hope I helped!

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3 years ago

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Mr hatch bout 4 round trip airplane tickets for $417 each. he also paid $50 in baggage fees. how much did mr hatch spend?

olga nikolaevna [1]

He spent $467 and you misspelt bought.

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3 years ago

Twice the difference of a number and 2 is equal 8

Vesnalui [34]

The answer would be 2x-8=3x-5 not sure though so double check

8 0

4 years ago

How many years will it take for a sum of money to double at 10% compounded annually

Bond [772]

Answer:

t=7.27 years

Step-by-step explanation:

Let the money be p and t will be the number of years that will be needed for the money to get double.

ATQ, 2p=p*(1+0.1)^t

2=(1.1)^t

log(2)/log(1.1)=t, t=7.27

5 0

3 years ago

One sample has a mean of M= 6, and a second sample has a mean of M = 12. The two samples are combined into a single set of score

lakkis [162]

Answer:

a) 9

b) 10

c) 8

Step-by-step explanation:

We are given the following in he question:

Mean of sample A = 6

Mean of sample B = 12

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$\dfrac{\displaystyle\sum x_a}{n_a} = 6\\\\\dfrac{\displaystyle\sum x_b}{n_b} = 12$

a) original samples have n = 4 scores

$\dfrac{\displaystyle\sum x_a}{4} = 6,\sum x_a = 24\\\\\dfrac{\displaystyle\sum x_b}{4} = 12,\sum x_b = 48\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{4+4}=\frac{24 + 48}{4 + 4} = 9$

b) first sample has n = 3 and the second sample has n = 6

$\dfrac{\displaystyle\sum x_a}{3} = 6,\sum x_a = 18\\\\\dfrac{\displaystyle\sum x_b}{6} = 12,\sum x_b = 72\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{3+6}=\frac{18+72}{3+6} = 10$

c) first sample has n = 6 and the second sample has n = 3

$\dfrac{\displaystyle\sum x_a}{6} = 6,\sum x_a = 36\\\\\dfrac{\displaystyle\sum x_b}{3} = 12,\sum x_b = 36\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{6+3}=\frac{36+36}{6+3} = 8$

7 0

3 years ago