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2 years ago

What is the volume of the figure?

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

4 0

Answer:

47.12

Step-by-step explanation:

same as the last question

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HELP PLEASE!!!

ch4aika [34]

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

8 0

3 years ago

Every hour of training raises the salary

timurjin [86]

(10,1250),(20,1400)
slope = (1400 - 1250) / (20 - 10) = 150/10 = 15

so every hr of training raises the salary by $ 15

7 0

3 years ago

PLS TRY TO ANSWER ASAP.

Harrizon [31]

Answer:

0.075 m/min

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

1. Write the equation for the volume of the cone:

$V=\dfrac{1}{3}\pi r^2h$

2. Find the relation between the radius and the height:

r = diameter/2 = 5m/2 = 2.5m

h = 5.2m

h/r =5.2 / 2.5 = 2.08

3. Filling the tank:

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

x/y=r/h

y = x . h / r

The volume of water inside the cone is:

$V=\dfrac{1}{3}\pi x^2y$

$V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3$

4. Find the derivative of the volume of water with respect to time:

$\dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}$

5. Find x² when the volume of water is 8π m³:

$V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\ 11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062$ m²

6. Solve for dx/dt:

$1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=0.03596m/min$

7. Find dh/dt:

From y/x = h/r = 2.08:

$y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min$

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0

3 years ago

Which of the following is a solution to the equation 1649

Alexeev081 [22]

Answer:

But what do we have to do ? like add subtract or multiply? i dont know

Step-by-step explanation:

5 0

3 years ago

Find the sum of the infinite series 1/3 + 4/9 + 16/27 64/81... if it exists.

nata0808 [166]

Answer:

It does not exist.

Step-by-step explanation:

If we divide the second term by the first, 3rd by the 2nd and the 4th by the 3rd we get a constant result 4/3.

So this is a Geometric Series with common ratio r = 4/3 and a1 = 1/3.

As the common ratio is greater than 1 the series diverges ( continues to get bigger) so there is no sum to infinity. It just goes on getting bigger and bigger without bounds.

8 0

3 years ago