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djverab [1.8K]
3 years ago
6

"Which ranges describe the cluster in the scatter plot?

Mathematics
2 answers:
Minchanka [31]3 years ago
7 0
A.between 8 and 10 years of age,
<span>C.between 10 and 12 years of age

</span>

lana66690 [7]3 years ago
6 0
The correct answers are: A and C <---------
    
          Hope i helped!:)
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Find the area of the shaded polygon.
Inessa [10]

Answer:

  • 8 square units

Step-by-step explanation:

Split the polygon into 3 triangles as pictured below

<u>They have base and height:</u>

  • 4 and 3, 1 and 1, 3 and 1

<u>Find the area of 3 triangles and add up:</u>

  • A = 1/2bh
  • A = 1/2*4*3 + 1/2*1*1 + 1/2*1*3 = 6 + 1/2 + 3/2 = 8 square units

6 0
3 years ago
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Order the following greatest to least <br><br> 1. 10kg<br> 2. 100g<br> 3. 1,000,000mg
svlad2 [7]

Answer:

<em>1, 2, 3</em>

Step-by-step explanation:

Of the three units, the <em>kilogram</em> is the largest and the <em>milligram</em> is the smallest. The prefix “<em>kilo</em>” means a thousand and “<em>milli</em>” means one-thousandths.

1,000,000mg = 1kg  

1kg = 1,000g

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2 years ago
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A circle has a diameter of 9cm
Katen [24]

For the square to fit inside the circle without touching it, the diagonal of the square needs to be less than the diameter of the circle.

Using the Pythagorean theorem we can calculate the diagonal of the square:

X = SQRT(5^2 + 5^2)

X = SQRT(25 + 25)

X = SQRT(50)

X = 7.07

The diagonal of the square is 7.07 cm, which is less than the diameter of the circle, 9cm, so it will fit .

8 0
3 years ago
How much money should be invested now (rounded to the nearest cent), called the initial investment, in a Treasury Bond investmen
Gre4nikov [31]
8519.54 should be the right answer
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3 years ago
Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio
lina2011 [118]

Answer:

The point of intersection is:

\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

y=0.5x+5

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is (0, 5), <em>h</em> = 0 and <em>k</em> = 5. The radius is 3. So, <em>r</em> = 3. Substitute:

(x-0)^2+(y-5)^2=(3)^2

Simplify:

x^2+(y-5)^2=9

At the point where the two equations intersect, its <em>x-</em>coordinate and <em>y-</em>coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for <em>x</em>. So:

x^2+((0.5x+5)-5)^2=9

Simplify:

x^2+(0.5x)^2=9

Square:

x^2+0.25x^2=9

Combine like terms:

\displaystyle 1.25x^2=\frac{5}{4}x^2=9

Solve for <em>x: </em>

<em />\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}<em />

Note that since we are looking for the point of intersection in QI, <em>x</em> should be positive. So, we can ignore the negative answer.

To find the <em>y-</em>coordinate, substitute the <em>x-</em>value back into either equation. Using the linear equation:

\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34

So, the point of intersection in QI is:

\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)

6 0
2 years ago
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