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max2010maxim [7]
3 years ago
6

What equation could be used to find the number of minutes, m, in h hours?

Mathematics
1 answer:
sammy [17]3 years ago
3 0
The equation would be 60h=m
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The radius of the base of a cylinder is increasing at a rate of 777 millimeters per hour. The height of the cylinder is fixed at
Tatiana [17]

Answer:

252<em>π</em>  or 791.7 mm³/h

Step-by-step explanation:

The volume of a cylinder is given by

V = \pi r^2h

We desire to find the volume rate, that is,\dfrac{dV}{dt}

\dfrac{dV}{dt} = \dfrac{dV}{dr}\cdot\dfrac{dr}{dt}

<em>dr/dt</em> is the rate of change of the radius which is 7 mm/h.

<em>dV/dr</em> is derived by differentiating the volume equation, yielding

\dfrac{dV}{dt} = 2\pi rh

At <em>r</em> = 12 mm and <em>h</em> = 1.5 mm,

\dfrac{dV}{dt} = 2\pi\times12\times1.5\times7 = 252\pi = 791.7

5 0
3 years ago
Subtract. Simplify, if possible.<br> 5/8<br> -<br> * 2 1 / 2 - 3
Nat2105 [25]

2\frac{1}{2} - \frac{5}{8}

Convert the mixed number to an improper fraction:

\frac{5}{2} - \frac{5}{8}

Subtract the fractions to get your final answer:

\frac{15}{8}

8 0
3 years ago
A Farmer plants the same amount everyday, adding up to 1 3/4 acres at the end of the year. If the year is 1/2 over how many acre
DochEvi [55]

Answer:

1/45 acres the farmer planted

8 0
3 years ago
Which statements are true about the solid, which has a length of 6 inches, a width of 3 inches, and a height of 2 inches?
bonufazy [111]
The volume would be 36 cubic inches.
7 0
3 years ago
Solve the following System of Three Equations:<br> x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
SashulF [63]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer:  {x = -3 , y = 4 , z = 0

4 0
3 years ago
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