Answer:
- <u>The correct statement is the first one: </u><u><em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean</em></u><em> </em>
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Explanation:
To calculate how many<em> standard deviations</em> a particular value in a group is from the mean, you can use the z-score:

Where:
is the number of standard deviations the value of x is from the mean
is the mean
is the standard deviation
Substitute in the formula:

Which means that <em>the number of blue-eyed students in Mr. Garcia's class is 2 standard deviations</em> above the mean.
Above the mean is the same that to the right of the mean, because the in the normal standard probability graph the central value is Z = 0 (the z-score of the mean value is 0), the positive values are to the right of the central value, and the negative values are to the left of the central value.
Therefore, the correct statement is the first one: <em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean, </em>
Answer:
e = 1/2
Step-by-step explanation:
to solve foe e in this 4/3=-6e-5/3
solution
4/3=-6e-5/3
4/3 + 5/3 = 6e
find the lcm of the left hand side
4 + 5/3 = 6e
9/3 = 6e
cross multiply
3 x 6e = 9 x 1
18e = 9
divide both sides by the coefficient of e which is 18
18e /18 = 9/18
e = 1/2
therefore the value of e in the expression above is evaluated to be equals to 1/2
Triangular sequence = n(n + 1)/2
If 630 is a triangular number, then:
n(n + 1)/2 = 630
Then n should be a positive whole number if 630 is a triangular number.
n(n + 1)/2 = 630
n(n + 1) = 2*630
n(n + 1) = 1260
n² + n = 1260
n² + n - 1260 = 0
By trial an error note that 1260 = 35 * 36
n² + n - 1260 = 0
Replace n with 36n - 35n
n² + 36n - 35n - 1260 = 0
n(n + 36) - 35(n + 36) = 0
(n + 36)(n - 35) = 0
n + 36 = 0 or n - 35 = 0
n = 0 - 36, or n = 0 + 35
n = -36, or 35
n can not be negative.
n = 35 is valid.
Since n is a positive whole number, that means 630 is a triangular number.
So the answer is True.
Both lines intersect at the point
(-0.5, 0.5)