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hammer [34]
4 years ago
8

1. This is the graph of which equation? You may want to use x and y intercepts to help you decide.

Mathematics
1 answer:
stepan [7]4 years ago
8 0
1. <span>5x + 5y = 25
2. </span><span>4x + y = 5
3. </span><span>4x - 6y = 24</span>
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Use the distributive property to solve the equation.<br> 2 (x – 9) = 10
scoundrel [369]

Answer:

x = 14

Step-by-step explanation:

Hi,

To begin, distribute the 2 to the x and -9.

So...

2 ( x - 9 ) = 10

2x - 18 = 10

2x = 28

x = 14

I hope this helps :)

5 0
3 years ago
Please answer correctly
Phoenix [80]

Answer:

26

Step-by-step explanation:

18 - 2^4 * (-0.5)

Calculate 2 to the power of 4 and get 16.

18−16(−0.5)

Multiply 16 and −0.5 to get −8.

18−(−8)

The opposite of −8 is 8.

18+8

Add 18 and 8 to get 26.

26

8 0
3 years ago
Pls help first one gets brainliest (must show work)
worty [1.4K]

Answer:

I got this. Use the order PEMDAS search Up if you don’t know what it means.

Step-by-step explanation:

Start with What’s inside the parentheses

(X - 3) = 3x

(X + 5) = 5x

The divide.

How to divide it - The number coefficients are reduced the same as in simple fractions. When dividing variables, you write the problem as a fraction. Then, using the greatest common factor, you divide the numbers and reduce. You use the rules of exponents to divide variables that are the same — so you subtract the powers.

3 0
3 years ago
Read 2 more answers
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
The question is in the pic :)
Scrat [10]
I think it’s either a or d
8 0
2 years ago
Read 2 more answers
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