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3 years ago

1. This is the graph of which equation? You may want to use x and y intercepts to help you decide.

Mathematics

1 answer:

stepan [7]3 years ago

8 0

1. 5x + 5y = 25
2. 4x + y = 5
3. 4x - 6y = 24

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Old McDonald had a farm. In one pen the old farmer had chickens and bulls together. In that pen there were 40 animals in total,

SVETLANKA909090 [29]

Answer:

There are 15 numbers of chicken and 25 numbers of bulls.

Step-by-step explanation:

The pen had chickens and bulls. The pen contains 40 animals in total. The number of legs in the pen is 130 .

Let

a = number of chicken

b = number of bull

a + b = 40................(i)

A chicken has 2 legs and a bull has 4 legs.

The total legs can be represented as

2a + 4b = 130...........(ii)

combine the equation

a + b = 40................(i)

2a + 4b = 130...........(ii)

a = 40 - b

insert the value of a in equation(ii)

2(40 - b) + 4b = 130

80 - 2b + 4b = 130

80 + 2b = 130

2b = 130 - 80

2b = 50

divide both sides by 2

b = 50/2

b = 25

Insert the value of b in equation (i)

a + b = 40

a + 25 = 40

a = 40 - 25

a = 15

There are 15 numbers of chicken and 25 numbers of bulls.

8 0

2 years ago

The sum of 6 times a number and 7 is equal to 5

inessss [21]

Answer:

6*x*7=5 or x*42=5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the area of the semicircle?

Serggg [28]

Step-by-step explanation:

$Area (semi-circle)= \frac{r^2\pi }{2}$

$A = \frac{(11)^2\pi }{2}$

$A=\frac{121\pi }{2}$

$A=\frac{379.94}{2}$

$A=189.97$

The area of the semi-circle is 189.97

6 0

2 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
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(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
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sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
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\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
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\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

2 years ago

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o

ycow [4]

Answer:

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,