The log of this is 15 because I multiplied 5•3 that gave me 15 so the answer to this problem is 15
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.






Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is
.
Therefore, the radius of given circle would be 18 cm.
Answer:
7
Step-by-step explanation:
arithmetic sequence: aₙ = a₁ + (n-1)d
a₈ = (-5) + (8-1)d = 37
7d = 42
d = 6
a₃ = -5 + (3-1) x 6 = 7
Answer:
see below
Step-by-step explanation:
If (x+5) is a factor of p(x), then the value x=-5 will make that factor be zero. The product p(x) of which it is a part will also be zero, so p(-5) = 0.
Since p(-5) = 0 at x=-5, there will be an x-intercept at x=-5.
Dividing something by a factor of that thing will always give a remainder of zero. So, p(x)/(x+5) has a remainder of 0.