Answer:
two solutions : (-3;4) and (-5;6)
Step-by-step explanation:
hello :
X²+y²+18x+29=0 ..(1)
X+y=1 ...(2)
by (2) : y = 1 - x
put this value in (1) : x² +(1-x)² +18x+29 = 0
x² +1 +x² -2x+18x +29 =0
2x²+16x +30 = 0
x²+8x+15 =0
delta = b²-4ac a=1 b=8 c = 15
delta = (8)²-4(1)(15)=64-60 =4 = 2²
X1=(-8+2)/2 = - 3
X2=(-8-2)/2 = - 5
case 1 : x = -3 y = 1 - (-3) = 4
case 2 : x = -5 y = 1 - (-5) = 6
Answer: 
Step-by-step explanation:
By definition, a relation is a function if and only if each input value has one and only one output value.
For this exercise it is important to remember that thw "Input values" are the values of the variable "x"and the "Output values" are the values of the variable"y".
In this case you have the following function provided in the exercise:

Then, to solve this exercise, you need to follow these steps:
Step 1. You have to substitute
into the function given.
Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")
You get that this is:

Answer:
Nolan took 97.75 seconds. you may need to round it to 98.
Step-by-step explanation:
multiply 15% by 85 which equals 12.75 then add to 85
Answer:
9,025
Step-by-step explanation:
9,500 multiplied by 0.95