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2 years ago

First use front end rounding to estimate the answer. Then multiply to find the exact answer.

Mathematics

2 answers:

iren2701 [21]2 years ago

4 0

Answer:

Estimated answer = 57.0

Exact answer = 54.04

Step-by-step explanation:

Since 19.3 is lesser than 19.5, it will be rounded down to 19.0

Since 2.8 is greater than 2.5, it will be rounded up to 3.0

Estimated multiplication

19.0 * 3.0 = 57.0

Actual multiplication

19.3 * 2.8 = 54.04

ss7ja [257]2 years ago

3 0

Answer:

Estimate = 57

Exact = 54.04

Step-by-step explanation:

We are given two number which we are to estimate by rounding off by front end and then multiply the exact values.

Front end estimate:

19.3 ---> 19

2.8 ---> 3

19 x 3 = 57

Exact multiplication:

19.3 x 2.8 = 54.04

Using front end rounding, we get an estimate of 57 while multiplying the exact numbers we get 54.04.

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The sum of two segments are 75 cm, and one the segments are four times the other. Calculate the measurement of each segment

iVinArrow [24]

The length of one segment is 15 cm and other segment is 60 cm

Step-by-step explanation:

Let x be the length of one segment and y be the length of other segment

Then according to given statement

x+y=75 Eqn 1

And

one the segments are four times the other

x=4y Eqn 2

$Putting\ x=4y\ in\ equation\ 1$

$4y+y=75\\5y=75\\Dividing\ both\ sides\ by\ 5\\\frac{5y}{5}=\frac{75}{5}\\y=15\\Putting\ y=15\ in\ eqn\ 2\\x=4(15)\\x=60$

Hence,

The length of one segment is 15 cm and other segment is 60 cm

Keywords: Linear Equation, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit

jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} ; x > 0$

Here, $\lambda$ = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean = $\frac{1}{\lambda}$

So, $22=\frac{1}{\lambda}$ ⇒ $\lambda=\frac{1}{22}$

SO, X ~ Exp( $\lambda=\frac{1}{22}$ )

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

$P(X\leq x) = 1 - e^{-\lambda x}$ ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

P(X < 30) = $1 - e^{-\frac{1}{22} \times 30}$

= 1 - 0.2557

= 0.7443

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Y_Kistochka [10]

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