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krek1111 [17]
3 years ago
10

A direct variation function contains the points (-8,-6) and (12,9) which equation represents the function

Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer:

y = 0.75x

Step-by-step explanation:

Given y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k substitute either of the 2 points into the equation

Using (12, 9 ), then

k = \frac{y}{x} = \frac{9}{12} = 0.75, so

y = 0.75x ← equation of variation

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Zinaida [17]

Answer:

The 3rd one 50 - 12p = 26

Step-by-step explanation:

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4 years ago
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6s-4=8 (2+ 0.25s)<br> solve for s
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Answer:

s=5

Step-by-step explanation:

6s-4=16+2s

6s=20+2s

4s=20

s=5

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3 years ago
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Biologists have found that the number of chirps some crickets make per minute is related to temperature. the relationship is ver
aalyn [17]

Answer:

It is 74.24 degrees Fahrenheit when the crickets are chirping 150 times a minute.

Variables x = Chirps and  y = Degrees

y-intercept = 38.24

slope = 0.24

Step-by-step explanation:

As the chirps are 124 times per minute for 68 degrees Fahrenheit we will consider it in (x_1,y_1) = (124,68).

Now when the chirps are 172 times and temperature is 80 degrees we consider it (x_2,y_2) = (172,80).

To find the slope we can use point-slope formula.

Where m is the slope and m=\frac{y_2-y_1}{x_2-x_1} =\frac{80-68}{172-124}= 0.24

To find y-intercept we will plug out the value of slope in y=m(x)+b choosing point (x_1,y_1) = (124,68).

So b=y-m(x) =68-124(0.24) =68-29.76=38.24

And the equation is y=0.24(x)+b

To calculate temperature for 150 chirpings we have to plug x=150 and b=38.24 in our above equation which is in form of y=m(x)+b

y=0.24(x)+b

y=0.24(150)+38.24=74.24\approx 75 degrees Fahrenheit.

Finally we have :

Temperature 74.24 degrees Fahrenheit.

With variables x = Chirps and  y = Degrees

y-intercept = 38.24 and

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6 0
3 years ago
In 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alc
Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol​ has changed.

Step-by-step explanation:

We are given that in 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alcoholic​ beverages?"

Of the 1100 adults​ surveyed, 429 indicated that they were total abstainers. In a recent​ survey, the same question was asked of 1100 adults and 352 in

<u><em>Let p = proportion of adults who totally abstain from alcohol.</em></u>

where, p = \frac{429}{1100} = 0.39

So, Null Hypothesis, H_0 : p = 39%      {means that the proportion of adults who totally abstain from alcohol​ has not changed}

Alternate Hypothesis, H_A : p \neq 39%      {means that the proportion of adults who totally abstain from alcohol​ has changed}

The test statistics that would be used here <u>One-sample z proportion statistics</u>;

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The value of z test statistics is -4.976.

<em>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</em><em> </em>

<em>Since our test statistics doesn't lie within the range of  critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the proportion of adults who totally abstain from alcohol​ has changed.

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