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2 years ago

What are the zeros of 3x squared-5x+2?

Mathematics

1 answer:

vodomira [7]2 years ago

5 0

3x² - 5x +2 = 3x² -3x-2x+2=3x(x-1) - 2(x-1)= (x-1)(3x-2)

(x-1)(3x-2)=0

x-1=0 or 3x-2=0

x=1 or x=2/3

Zeros are x=1, x=2/3.

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2 years ago

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2 years ago

Which is equivalent to x^3 y^-7

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For this case we must find an expression equivalent to:

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2 years ago

Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She

Ghella [55]

Answer:

The correct answer is option (E)

Step-by-step explanation:

Solution to the question

Let us recall from given question that,

H0:p=0.80

Ha:p≠0.80 (which is the two tailed test)

For the p-value we have,

P-value: Let us assume that the null hypothesis is true, then the probability of observing the sample statistics or the more extreme,

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2 years ago

A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.

galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: $(x-h)^2+(y-k)^2=r^2$ , where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:

NE = $\sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}$

The radius is √34, which means that r² = 34. So, our equation is:

(x + 6)² + (y + 2)² = 34

Plug in -10 for x and -7 for y:

(x + 6)² + (y + 2)² = 34

x² + 12x + 36 + y² + 4y + 4 = 34

x² + 12x + y² + 4y + 40 = 34

x² + 12x + y² + 4y + 6 = 0

(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7

Since 7 > 0, we know that H lies outside the circle.

6 0

3 years ago

Read 2 more answers