You can reduce the first one by combining the ab and the ba term
Area of a rectangle = Length * Width
Area = 60cm^2
Length = 4
Width = GH = ? = x
60 = 4*x
solve for x
60/4 = x
x = 15
GH is 15cm
Answer:
c
Step-by-step explanation:
c
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
Answer:
x=70
y= 40
Step-by-step explanation:
the triangle containing x is an isosceles triangle so two of the sides are 55.
55+55+x=180.
110+x=180
110-110+x=180-110
x=70
Triangle BAC is equilateral so 180/3=60. Now
x+60+c=180
70+60+c=180
130+c=180
130-130+c=180-130
c=50
That gives us one corner of triangle CBD. We know a second angle is 90 so
50+90+y=180
140+y=180
140-140+y=180-140
y=40
I think that is correct but you are free to check it yourself
