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Nady [450]
3 years ago
8

Whats 0.68% of 425show your work

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Find 0.68% as a fraction:

\frac{0.68}{100}=\frac{68}{10000}=\frac{17}{2500}

So you multiply that by 425 to get your value:

\frac{17}{2500}*\frac{425}{1}=\frac{17}{100}*\frac{17}{1}=\frac{17*17}{100}=\frac{289}{100}

Your answer is \frac{289}{100} or, in decimal format, 2.89.

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leonid [27]
<span>2 square root (x - 5) = 2. 2^2 (x -5) = 2^2. 4(x - 5) = 4. 4x - 20 = 4. 4x = 24. x = 6. This solution is not extraneous, because extraneous solutions emerge from solving the problem but are not actually valid solutions for the initial problem. With rounding, this solution is valid for the initial problem.</span>
8 0
3 years ago
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500th term of 24,31,38,45,52
tensa zangetsu [6.8K]
This looks like a simple arithmetic series. Each term is 7 greater than the previous term.

Therefore, the Nth term is 17 + 7N. 

For example, the first term is 17 + 7*1 = 17 + 7 = 24.

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3 0
3 years ago
Simplify: 3x(x^2 + 4x - 5)
Alina [70]

Answer:

3x^3+ 12x^2-15x

Step-by-step explanation:

First, you would have to distribute the 3x to everything in the parentheses. So you can write it out as (3x*x^2)+(3x*4x)+(3x*5). Solving this will give you the answer. We'll start off with (3x*x^2). Because we are MULTIPLYING, this part will equal to 3x^3. There is ONE x with 3x (think of it as 3x^1) and 2 x's in x^2, having a total of 3 x's, or x^3. Since the 3 is being multiplied as well, we can write it as 3x^3.

Second, we will solve (3x*4x). We are multiplying, so first we multiply 3*4 and then x*x. 3*4 is 12 and x*x is x^2.  There are 2 x's being mutipled by each other, so the x becomes squared. Now we finish and multiply 12*x^2 wich is 12x^2.

Lastly, we solve (3x*5). 3x is being multiplied 5 times which gives us 15x.

I hope this helped :)

3 0
3 years ago
What are the first 6 nonzero multiples of 15?
Sphinxa [80]
<span>5,10,15,20,25,30,35,40,45,50,55,60 or 6,12,18,24,30,36,42,48,54,60,66,72</span>
8 0
3 years ago
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Carl coaches a youth basketball team. Pat is one of the players on the
lisabon 2012 [21]

the q3 is just above the median so

Step-by-step explanation:

its higher by 5

7 0
3 years ago
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