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tresset_1 [31]
3 years ago
5

Drag the correct classification for each graph into the boxes to complete the table.

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0
An even function has a graph  that is symmetric about the Y axis
and odd function is symmetric about the x axis
 1st graph = odd
2nd graph =  neither
3rd graph = even



poizon [28]3 years ago
5 0

Answer:

1st graph - Odd Function

2nd graph - Neither odd nor even function

3rd graph - Even Function

Step-by-step explanation:

We know that,

Even functions are the functions whose graphs are symmetric with respect to y-axis.

Odd functions are the functions whose graphs are symmetric with respect to the origin.

From the options, we have that,

1st graph is symmetric about the origin and is the graph of the line f(x)=x.

So, f(-x)=-x=-f(x)

The first graph is the graph of an odd function.

2nd graph can be seen that is neither symmetric about the y-axis nor the origin.

The second graph is neither and odd function nor an even function.

3rd graph is symmetric about the line of the form y=c, where 'c' is some constant.

The third graph is the graph of an even function.

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c = 2 × 14.6 × π = 29.2 × 3.141592 = 91.7344864 ≈ 91.7

Correct anawer:  B



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3 years ago
A cylindrical base has a diameter of 6 inches. At the bottom of the vase, there are 9 marbles, each of the diameter 3 inches. Th
alexandr1967 [171]

Answer:

\sf C. \quad \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

Step-by-step explanation:

To find the volume of water in the vase, subtract the volume of the marbles from the volume of the cylindrical vase.

..............................................................................................................................

The marbles can be modeled as <u>spheres</u>.

<u>Volume of a sphere</u>

\sf V=\dfrac{4}{3}\pi r^3 \quad \textsf{(where r is the radius)}

<u>Radius</u>

\sf r = \dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

Therefore, the volume of 9 marbles, each of diameter 3 inches is:

\sf Volume & = \sf 9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

..............................................................................................................................

The vase can be modeled as a <u>cylinder</u>.

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad \textsf{(where r is the radius and h is the height)}

Therefore, the volume of a cylinder with a base of diameter 6 in and a height of 12 in is:

\sf Volume =\pi (3\:in)^2(12\:in)

..............................................................................................................................

<u>Volume of water</u>

<u />

\begin{aligned}\implies \sf Volume\:of\:water & = \sf Volume\:of\:vase- Volume\:of\:marbles\\& = \sf \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)\end{aligned}

8 0
2 years ago
78999999×34556 <br><br>answer this pelease​
Schach [20]

2.729924 about because some of it is a non existant number. Also 2.729924 is the closest you can get to the answer.

4 0
3 years ago
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The graph of a function f(x) is shown below:
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The last one is the answer. it goes from the smallest input to the largest input also known as the domain
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