The volume of a figure is the number of cubic units present in the figure. For this problem, we assume that the figure would be a rectangular box in shape. So, the volume would be calculated by the product of its length, width and height or in this case the depth. We calculate the volume of water as follows:
Volume = 4.50 ft x 7.00 ft x 5.00 in ( 1 ft / 12 in )
Volume = 13.125 ft^3
We need to convert the resulting volume in liters. We do as follows:
Volume = 13.125 ft^3 ( 0.3048 m / 1 ft )^3 ( 1000 L / 1 m^3 )
Volume = 371.66 L
Answer:
A.9
B.6
C.7
D.1
E.5
F.4
G.2
H.3
I.8
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Answer:
C. (-1, 2) and (4, 7)
Step-by-step explanation:
It may be simplest just to try the answer choices.
We notice that y = x+3 is not satisfied by the points in choices A or D, so those can be eliminated.
__
The second equation can be written in vertex form as ...
y = (x -1)^2 -2
This equation is not satisfied by the points of choice B.
Using (-1, 4) (from choice B), we get 4 = (-1-1)^2 -2 = 4-2 = 2 . . . FALSE.
However it is a good match for the points of choice C.
Using (-1, 2) (from choice C), we get 2 = (-1-1)^2 -2 = 4 -2 = 2 . . . True
The appropriate choice is ...
(-1, 2) and (4, 7)
I got 5x^2 - 30x................
Answer:
10r²
Step-by-step explanation:
The following data were obtained from the question:
Radius (r) = 5r
Length of arc (L) = 4r
Area of sector (A) =?
Next, we shall determine the angle θ sustained at the centre.
Recall:
Length of arc (L) = θ/360 × 2πr
With the above formula, we shall determine the angle θ sustained at the centre as follow:
Radius (r) = 5r
Length of arc (L) = 4r
Angle at the centre θ =?
L= θ/360 × 2πr
4r = θ/360 × 2π × 5r
4r = (θ × 10πr)/360
Cross multiply
θ × 10πr = 4r × 360
Divide both side by 10πr
θ = (4r × 360) /10πr
θ = 144/π
Finally, we shall determine the area of the sector as follow:
Angle at the centre θ = 144/π
Radius (r) = 5r
Area of sector (A) =?
Area of sector (A) = θ/360 × πr²
A = (144/π)/360 × π(5r)²
A = 144/360π × π × 25r²
A = 144/360 × 25r²
A = 0.4 × 25r²
A = 10r²
Therefore, the area of the sector is 10r².