1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lilit [14]
3 years ago
14

Sam sells necklaces for $10 each. Each necklace costs her $5 to make. She also has $5,000 in fixed costs per year for her jewelr

y business. How many necklaces must she sell in order to make a profit of $1,000 in one year? A. 200 B. 600 C. 100 D. 1200
Mathematics
1 answer:
Marina CMI [18]3 years ago
4 0

profit = revenue - expenses

Filling in the given values, where n is the number of necklaces Sam must sell ...

... 1000 = 10n - (5n +5000)

... 6000 = 5n . . . . . . collect terms, add 5000

... 1200 = n . . . . . . . divide by 5

The appropriate choice is

... D. 1200

You might be interested in
Several children are standing in line to ride a roller coaster. Their heights, in inches, are 59, 68, 58, 65, 62, 68, 67. What i
Brrunno [24]
65 because if you put all the numbers in order and work out which one is in the middle you get the median. i enjoy using the rhyme. Hey diddle diddle, the medians the middle, you add then divide for the mean, the mode is the one that you see the most and the range is the difference between.
8 0
3 years ago
Can someone please answer this???? ASAP
timofeeve [1]

Answer:

A. y=-\dfrac{8}{7}x-\dfrac{18}{7}

Step-by-step explanation:

Let y=mx+b be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is \frac{7}{8} Hence,

\dfrac{7}{8}\cdot m=-1\\ \\m=-\dfrac{8}{7}

is the slope of needed line.

This line passes through the point (-4,2), so its coordinates satisfy the equation:

2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}

Therefore, the equation of the line is

y=-\dfrac{8}{7}x-\dfrac{18}{7}

7 0
3 years ago
On an uphill hike, Ted climbs at a rate of 3 miles an hour. Going down, he runs at a rate of 5 miles an hour. If it takes him 40
telo118 [61]

It takes 40 minutes more going up or 40/60 = 0.67 hours more.

Let us say that:

t = the time required for him running down

t + 0.67 = time required for him running up

 

Since the distance of running up and down must be equal therefore:

(3 miles / hr) * (t + 0.67) = (5 miles / h) * t

3 t + 2.01 = 5 t

2 t = 2.01

t = 1.005 hr

 

So the total length of the hike is:

length = 2 * (5 miles / hr) * (1.005 hr)

<span>length = 10.05 miles</span>

3 0
3 years ago
Read 2 more answers
3+2−16⋅9=?<br> can you help me
wel
-99..?? I think that’s the answer
7 0
3 years ago
Read 2 more answers
find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0​
Citrus2011 [14]

Answer:

Radius: r =\frac{\sqrt {21}}{6}

Center = (-\frac{3}{2}, -\frac{2}{3})

Step-by-step explanation:

Given

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Solving (a): The radius of the circle

First, we express the equation as:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

So, we have:

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Divide through by 9

x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0

Rewrite as:

x^2  + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}

Group the expression into 2

[x^2  + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

Next, we complete the square on each group.

For [x^2  + 3x]

1: Divide the coefficient\ of\ x\ by\ 2

2: Take the square\ of\ the\ division

3: Add this square\ to\ both\ sides\ of\ the\ equation.

So, we have:

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

[x^2  + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Factorize

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Apply the same to y

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}

Add the fractions

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

Recall that:

(x - h)^2 + (y - k)^2 = r^2

By comparison:

r^2 =\frac{7}{12}

Take square roots of both sides

r =\sqrt{\frac{7}{12}}

Split

r =\frac{\sqrt 7}{\sqrt 12}

Rationalize

r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}

r =\frac{\sqrt {84}}{12}

r =\frac{\sqrt {4*21}}{12}

r =\frac{2\sqrt {21}}{12}

r =\frac{\sqrt {21}}{6}

Solving (b): The center

Recall that:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

From:

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

-h = \frac{3}{2} and -k = \frac{2}{3}

Solve for h and k

h = -\frac{3}{2} and k = -\frac{2}{3}

Hence, the center is:

Center = (-\frac{3}{2}, -\frac{2}{3})

6 0
2 years ago
Other questions:
  • Look at this prism and its net. Rectangular prism with length labeled 5 meters, width labeled 7 meters, and height labeled 12 me
    9·1 answer
  • ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
    15·1 answer
  • Find M&lt;1 and M&lt;3 in the kite
    14·1 answer
  • How would you do 2 times 25 times 30
    10·2 answers
  • Probablity of getting a number greater than 4 when a die is rolled one time
    6·2 answers
  • What is i^2 simplified?
    5·2 answers
  • Jill made scarves and then sold them for $15 each. If Jill spent $150 to make all the scarves, how many scarves need to be sold
    7·2 answers
  • How do you graph a line when your equation is written as a fraction?
    13·1 answer
  • Once hundred and<br>eight<br>ht and two tens as a decimal ​
    9·1 answer
  • I don’t know how to do this
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!