Answer:
<em>(a) x=2, y=-1</em>
<em>(b) x=2, y=2</em>
<em>(c)</em> 
<em>(d) x=-2, y=-7</em>
Step-by-step explanation:
<u>Cramer's Rule</u>
It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.
It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

We call the determinant of the system

We also define:

And

The solution for x and y is


(a) The system to solve is

Calculating:





The solution is x=2, y=-1
(b) The system to solve is

Calculating:





The solution is x=2, y=2
(c) The system to solve is

Calculating:





The solution is

(d) The system to solve is

Calculating:





The solution is x=-2, y=-7
A straight line is 180 degrees. As a result, 180-35=x, or x=145
Answer:
Susan jogged 1 1/8 miles
Step-by-step explanation:
4 1/2= 18/4. 18/4 ÷ 1/4= 1.125= 1 1/8
Answer:
The order of operations requires that all multiplication and division be performed first, going from left to right in the expression.
Step-by-step explanation:
<u><em>8</em></u>, <em><u>6</u></em>, and <em><u>4</u></em>.
Eight plus six equals: 14
Then add four, and your get eighteen
<em>~Hope this helped :)</em>