Class records at rockwood college indicate that a student selected at random has probability 0.75 of passing french 101. for the
student who passes french 101, the probability is 0.91 that he or she will pass french 102. what is the probability that a student selected at random will pass both french 101 and french 102? (round your answer to three decimal places.)
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To get the probability of two individual events both occurring,
you have to multiply the probabilities of their individual events occurring. Therefore
in this problem, the probability that a student selected at random will pass
both French 101 and French 102 is 0.683 (.75 x .91). The answer is already
rounded to three decimal places.
We can use vertical opposite angles. Which means the opposite angles where 2 lines intersects is the same. 3x + 50 = 6x - 10 (vert. Opp. Angles) 3x = 6x - 60 -3x = - 60 X = 20°
