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Fittoniya [83]
3 years ago
11

Write the ratio of the first measurement to the second

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

60:49

Step-by-step explanation:

1ft = 12in

5 x 12 = 60

60:49

They share no common factors so this is your final answer.

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Draw the graph of f(x) = (x − 1)2 − 2. Start by creating a table of ordered pairs for the function. Then plot the points from th
pogonyaev

The attached graph represents the graph of f(x) = (x - 1)^2 - 2

<h3>How to plot the graph?</h3>

The equation is given as:

f(x) = (x - 1)^2 - 2

Next, we set x to -2, -1, 0, 1 and 2.

So, we have:

f(-2) = (-2 - 1)^2 - 2 = 7

f(-1) = (-1 - 1)^2 - 2 = 2

f(0) = (0 - 1)^2 - 2 = -1

f(1) = (1 - 1)^2 - 2 = -2

f(2) = (2 - 1)^2 - 2 = -1

This means that the table of values is

x      f(x)

-2    7

-1    2

0    -1

1     -2

2    -1

Next, we plot the above points and connect them.

See attachment for the graph of f(x) = (x - 1)^2 - 2

Read more about graphs and functions at:

brainly.com/question/4025726

#SPJ1

7 0
2 years ago
0.03, 0.031, 0.1, 0.013 smallest to largest
vitfil [10]

Answer:

0.013

0.031

0.03

0.1

I hope my answer's correct.

3 0
3 years ago
Pls help!!! thank you in advance​
Oliga [24]

answer simple

i thinks its b

5 0
3 years ago
Read 2 more answers
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️
Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0
2 years ago
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