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mylen [45]
3 years ago
10

Pls answer I cannot do it

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

a square number has and odd amount of numbers but 5to the power of 9 has an even amount of numbers

5×5×5×5×5×5×5×5×5

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The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.
Vladimir79 [104]
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0. 

-16t^2 + 16t = 0

-16t(t-1)=0

t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
7 0
3 years ago
How to solve:
natima [27]
Let the first be x  and the second be x + 4
x+ x + 4 = 56
2x+4 = 56
2x = 52
∴x= 26

please mark as brainliest
7 0
3 years ago
Read 2 more answers
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
Evaluate the expression for the given value of each variable.
makkiz [27]
I believe the answer should be 77
5 0
3 years ago
The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim
Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

34.5 + 20.75 + 24.75 = 80cm.

Hope this helped.

3 0
3 years ago
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