Answer:
5
Step-by-step explanation:
The mean is 6 and there are 5 intergers.
You'd multiply 5*6=30. That means that the sum is 30.
The values could be: 2 3 7 9 9
These values add up to 20
Have a mode of 9
Have a median of 7
Have a mean of 6
To find the range you would subtract 9 and 2. That gives you 5.
(i don't know if that's the greatest possible range. But 5 would be the range here)
A.25
Work:
-5x-5=25
Hope his helps.
Yes you are correct!
you first have to get rid of the number next to the variable m. so you have to subtract 9 to get rid of the variable. then you subtract 9 from both sides and get that answer.
Hello there,
The answer will be <u>1</u><u>5</u><u> </u><u>students.</u>
<h3>Step-by-step explanation:-</h3>
We will solve the equation as follows:-
First add the total of the students in band and chorus -
→ 70 + 95 = 165
Then subtract the previously got number with given number of chorus students:-
→ 165 - 150 = 15
So, there are <u>15 students</u> who are there in both band and chorus.
✍️ <em>By </em><em>Benjemin</em> ☺️
ffn
the sum of their squares is 110, So 
the sum of their cubes is 684, so 
the product of the three integers is 210, so xyz= 210
the sum of any two products (xy+yz+zx) is 107
Now we plug in all the values in the identity
684 - 3(210) = (x+y+z)(110-107)
684 - 630 = (x+y+z)(3)
54 = 3(x+y+z)
Divide by 3 on both sides
18 = x+y+z
the value of the sum of three integers is 18
