Closure property: If a and b are real numbers, a+b is also a real number.
- Associative property: a+(b+c) = (a+b)+c.
- Commutative property: a+b = b+a.
- Additive identity: a+0 = a.
- Additive inverse: a + (-a) = 0.
For Multiplication -
Answer:
Step-by-step explanation:
Nothing in the problem statement tells you anything about the directions of lines LK or QT, so you cannot conclude they are parallel. You only know that EV crosses CN and KT at right angles.
EJ ⊥ CN means m∠CJV = 90°, as all angles at the intersection of EJ and CN are 90°.
The mean exists at 3 and the standard deviation exists 0.87.
Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

<h3>What is the binomial probability distribution?</h3>
The expected value of the binomial distribution exists:

The standard deviation of the binomial distribution exists:

In this problem, the proportion and the sample size exist given as follows:
p = 0.75
n = 4
Therefore, the mean and the standard deviation exist given by:



The mean exists at 3 and the standard deviation exists 0.87.
To learn about the binomial distribution refer to:
brainly.com/question/24863377
#SPJ4
A(-4, -1)
B(-3, -3)
C(0, 2)
Answer:
If the time passed is only 3 months, then it is $2040
Step-by-step explanation:
We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt
Step 1: Find out how much 3 months is in a year
<em>In this case, 3/12 which is 1/4</em>
Step 2: Plug in known variables into equation
2000[1 + (0.08)/4)]^[(4)(1/4)]
Step 3: Solve/Plug in calc
You will get $2040
If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.