No. The circle can be composed of completely negative coordinates, but the radius is always a positive value. You can prove this by plugging any point and the center into the distance formula.
Answer:
uh no sorry ......... cant see pic at all
Step-by-step explanation:
-19, -12, 1/2, 1, 5, 12 ----> least to greatest
12, 5, 1, 1/2, -12, -19 ----> greatest to least
Do the same as the last one, starting with the largest negative number, and ending with the largest positive number. The only difference in this case is that it is greatest to least. I tend to go from least to greatest first and then flip it around to get greatest to least (:
Answer:
y = -3x -4
Step-by-step explanation:
A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.
The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.
The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...
3(x+3) +(y-5) = 0
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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:
3x +9 +y -5 = 0 . . . . . eliminate parentheses
y = -3x -4 . . . . . subtract terms that are not "y"
Three and seventy-five hundredths.
Hope I helped! :P