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Arada [10]
2 years ago
11

Pedro sliced 27 cakes. Each chocolate cake had 7 slices and each lemon cake had 6 slices. If Pedro made 170 slices in total, how

many of each type of cake did he slice?

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0

Answer:

Step-by-step explanation:

Let number of chocolate cakes = c

Number of lemon cakes = l

Total cakes = 27

c + l = 27 ---------------(I)

Total slices = 170

7c + 6l = 170  ---------------(II)

Multiply equation (i) by (-7) and then add. So, c will be eliminated and we can find the value of  l

(I) * (-7)        -7c - 7l = -189

(II)                <u>7c + 6l = 170  </u>   {Now add}

                         - l    = -19

l = 19

Plugin l = 19 in equation (I)

c + 19 = 27

c = 27 - 19

c = 8

Number of chocolate cakes = 8

Number of lemon cakes = 19

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It would be 3 cuz 16-4 =12  divide by 4 is 3
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3 years ago
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Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1
jek_recluse [69]

Answer:

S_{31}=71.3


Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

U_n=a_1+(n-1)d


We were given that the 9th term is 17.


\Rightarrow 17=a_1+(9-1)(-2.1)


\Rightarrow 17=a_1+(8)\times(-2.1)


\Rightarrow 17=a_1-\frac{84}{5}


\Rightarrow 17+\frac{84}{5}=a_1


\Rightarrow a_1=\frac{169}{5}


The sum of the first n-terms is given by the formula,


S_n=\frac{n}{2}(2a_1+(n-1)d)


To find S_{31}, we substitute n=31, a_1=\frac{169}{5} and d=-2.1.


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))



\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})


\Rightarrow S_{31}=\frac{713}{10}


\Rightarrow S_{31}=71.3


The correct answer is D















8 0
3 years ago
Read 2 more answers
-6h plus 4 - 3plus h equals 11
olga55 [171]

- 6h + 4 - 3 + h = 11
So we start by combining like terms;
- 6h + h =  - 5h
4 - 3 = 1
Now we have;
- 5h + 1 = 11
We then subtract 1 from both sides;
- 5h + 1 = 11
- 5h = 10
Then we divide both sides by 5;
- 5h = 10
- 5h \div  - 5h =  h
10 \div  - 5h =  - 2
Leaving the final answer to be h = -2
5 0
3 years ago
Jake bought 2 shirts and 1 pair of pants for $6. Mike bought 1 shirt and 1 pair of pants for $4. How much is each shirt and each
EastWind [94]

The cost of a shirt and a pair of pants is the same and is equal to $2. The correct option is B.

<h3>What is a solution to a system of equations?</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and as all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none)

Let x represent the cost of a shirt, while y represent the cost of a pair of pants.

Given that Jake bought 2 shirts and 1 pair of pants for $6. Therefore, the equation that represents this situation is,

2x + y = 6 ..... equation 1

Also, Mike bought 1 shirt and 1 pair of pants for $4. Therefore, the equation that represents this situation is,

x + y = 4

Solve the equation for x,

x = 4 - y

Substitute the value of x in equation 1,

2x + y = 6

2(4 - y) + y = 6

8 - 2y + y = 6

-y = 6 - 8

-y = -2

y = 2

Substitute the value of y in equation 1,

2x + y = 6

2x + 2 = 6

2x + 2 = 6

2x = 6 - 2

2x = 4

x = 4/2

x = 2

Hence, the cost of a shirt and a pair of pants is the same and is equal to $2.

Learn more about finding the solution graphically here:

brainly.com/question/26254258

#SPJ1

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