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Arada [10]
2 years ago
11

Pedro sliced 27 cakes. Each chocolate cake had 7 slices and each lemon cake had 6 slices. If Pedro made 170 slices in total, how

many of each type of cake did he slice?

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0

Answer:

Step-by-step explanation:

Let number of chocolate cakes = c

Number of lemon cakes = l

Total cakes = 27

c + l = 27 ---------------(I)

Total slices = 170

7c + 6l = 170  ---------------(II)

Multiply equation (i) by (-7) and then add. So, c will be eliminated and we can find the value of  l

(I) * (-7)        -7c - 7l = -189

(II)                <u>7c + 6l = 170  </u>   {Now add}

                         - l    = -19

l = 19

Plugin l = 19 in equation (I)

c + 19 = 27

c = 27 - 19

c = 8

Number of chocolate cakes = 8

Number of lemon cakes = 19

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3 years ago
Show that if X is a geometric random variable with parameter p, then
Lubov Fominskaja [6]

Answer:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

In order to find the expected value E(1/X) we need to find this sum:

E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}

Lets consider the following series:

\sum_{k=1}^{\infty} b^{k-1}

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}   (a)

On the last step we assume that 0\leq r\leq b and \sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}, then the integral on the left part of equation (a) would be 1. And we have:

\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)

And for the next step we have:

\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}

And with this we have the requiered proof.

And since b=1-p we have that:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

4 0
3 years ago
Plans Math Fourth grade &gt; W.4 Parallel sides in quadrilaterals 58M How many pairs of opposite sides are parallel? no pairs 1
AURORKA [14]

Answer:

2 pairs

Step-by-step explanation:

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5 0
3 years ago
−4(3m−3)+(−10+8m)=?
Valentin [98]
-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11


*note negative times a negative equals positive and negative times positive is negative 
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m 
sixth: combine like terms
seventh: answer
 
5 0
3 years ago
Help please! this is my third time posting this!! T.T
ArbitrLikvidat [17]

Answer:

see below

Step-by-step explanation:

24 - 3 x = -27

Subtract 24 from each side

24-24 - 3 x = -27-24

-3x =-51

Divide each side by -3

-3x/-3 = -51/-3

x = 17

Check

24 -3(17) = -27

24 -51 = -27

-27 = -27

8 0
3 years ago
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