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irina [24]
3 years ago
11

Mark worked at flea market one weekend selling electronic games. On the Saturday, he sold 7/12 of the games. Sunday morning he s

old 3/8 of the games and in the afternoon, he sold half of what remained. What fraction of the games did he sell in all ?

Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

23/24

Step-by-step explanation:

the picture explains the whole problem

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Which pair represents equivalent ratios? A Begin fraction . . . 2 over 3 . . . end fraction . . . and . . . begin fraction . . .
Blizzard [7]

Equivalent ratios are those ratios which are same that is on simplifying each of them, we will get the same answer.

A.\frac{2}{3} and \frac{9}{15} = \frac{3}{5}

So they are not equivalent

B.\frac{5}{8} and \frac{15}{21} = \frac{5}{7}

So they are not equivalent

C.\frac{3}{12} and \frac{6}{18} = \frac{1}{4} and \frac{1}{3}

They are not equivalent too.

D.\frac{4}{10} and \frac{12}{30} = \frac{2}{5} and \frac{2}{5}

And they are equivalent. SO the correct option is D .

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3 years ago
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MNOP is a square. What are the values of t and f?
djyliett [7]
The answer is: <span>t=17.5 and f=12
</span>
Hope this helps!!

~Lena~
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3 years ago
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Which equation represents a line which is parallel to x = 0
levacccp [35]
I really don’t no so sorry hope u find the asset if you haven’t
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3 years ago
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Doing research for insurance rates, it is found that those aged 30 to 49 drive an average of 38.7 miles per day with a standard
Alja [10]

Answer: 0.4302

Step-by-step explanation:

Given : Mean : \mu=\text{38.7 miles }

Standard deviation : \sigma=\text{6.7 miles }

Sample size : n=60

Also, these distances are normally distributed.

Then , the formula to calculate the z-score is given by :-

z=\dfrac{x-\mu}{\sigma}

For x=32.5

\\\\ z=\dfrac{32.5-38.7}{6.7}=-0.925373134\approx-0.93

For x=40.5

\\\\ z=\dfrac{40.5-38.7}{6.7}=0.268656\approx0.27

The p-value = P(-0.93

=P(0.27)-P(-0.93)=0.6064198- 0.1761855=0.4302343\approx0.4302

Hence, the required probability :-0.4302

3 0
3 years ago
1
zmey [24]

Answer:

Part 1) The inequality that represent this situation is 5(x+7)^{2} \geq1,050  or  5x^{2}+70x+245 \geq1,050

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ---->  the width of Andrew's tablet

we know that

L=5W ------> equation A

W=x+7 ----> equation B

The area of the television is

A=LW -----> equation C

Substitute equation A and equation B in equation C

A=5(x+7)(x+7)

A=5(x+7)^{2}

5(x+7)^{2} \geq1,050

5(x^{2}+14x+49) \geq1,050

5x^{2}+70x+245 \geq1,050 ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

For x=8 in

Substitute in the inequality

5(8+7)^{2} \geq1,050

5(15)^{2} \geq1,050

1,125 \geq1,050 -----> is true

therefore

Yes, 8 inches is a reasonable width for his tablet

3 0
3 years ago
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