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Gwar [14]
3 years ago
6

Find a recursive rule for the sequence 2 4 6 10

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

\bf 2~~,~~4~~,~~\stackrel{2+4}{6}~~,~~\stackrel{4+6}{10} ~\hfill \stackrel{n^{th}\textit{ value is the sum of the two before it}}{a_n=a_{n-2}+a_{n-1}} \\\\\\ ~\hspace{34em}

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BRAINLIEST TO CORRECT HURRY
stealth61 [152]

Answer: 3.5>-3

Step-by-step explanation:

3 0
3 years ago
Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select t
harkovskaia [24]

The equations which gave the same solution as; 2.3p – 10.1 = 6.5p – 4 – 0.01p are;

  • 2.3p – 10.1 = 6.49p – 4 and
  • 230p – 1010 = 650p – 400 – p

<h3>Which equations have the same solution as the given equation?</h3>

It follows from the answer choices that the equation; 2.3p – 10.1 = 6.49p – 4 is equivalent to the given equation as the algebraic sum of p variables is evaluated on the right hand side.

The second equation; 230p – 1010 = 650p – 400 – p also is equivalent to the given equation, when multiplied through by 100.

Read more on equivalent equations;

brainly.com/question/2972832

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4 0
2 years ago
If the function f(x)=mx+b has an inverse function, which statement must be true
skelet666 [1.2K]
Im pretty sure its
m=/0 because when m is 0 then f(x) does not depend on the value of x.
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7 0
3 years ago
Read 2 more answers
A quote you received from a local restaurant is $625 for a business luncheon. The restaurant owner tells you the price with grat
Kryger [21]
The correct answer would be A.

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3 years ago
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point f is inside regular pentagon abcde so that triangle abf is equilateral. Find all the angles of abcf, in degrees
Citrus2011 [14]

The equilateral triangle, and regular pentagon, gives the measure of the

angles formed from which the interior angles of ABCF can be found.

Response:

  • ∠BCF = 66°
  • ∠BAF = 60°
  • ∠CFA = 126°
  • ∠ABC = 108°

<h3>Which properties of figures can be used to find the interior angles?</h3>

The given parameters are;

The point in the regular pentagon is point <em>F</em>

ΔABF is an equilateral triangle

Required:

The angles in quadrilateral ABCF

Solution:

Given that ΔABF is an equilateral triangle, we have;

∠FBA = ∠BAF = ∠AFB = 60°

∠ABC = An interior angle of a regular pentagon = 108°

Which gives;

  • ∠FBC = 108° - 60° = 48°

∠BCF = ∠BFC = Base angles of an isosceles triangle ΔBCF

Which gives;

∠BCF + ∠BFC + 60° + 60° + 108° = 360°, angle sum property of a quadrilateral

2·∠BCF + 60° + 60° + 108° = 360°

2·∠BCF = 360° - (60° + 60° + 108° ) = 132°

∠BCF = 132° ÷ 2 = 66°

The interior angles of quadrilateral ABCF are;

  • ∠BCF =<u> 66°</u>
  • ∠BAF =<u> 60°</u>
  • ∠CFA = 66° + 60° = <u>126°</u>
  • ∠ABC =<u> 108°</u>

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4 0
2 years ago
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