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Gwar [14]
3 years ago
6

Find a recursive rule for the sequence 2 4 6 10

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

\bf 2~~,~~4~~,~~\stackrel{2+4}{6}~~,~~\stackrel{4+6}{10} ~\hfill \stackrel{n^{th}\textit{ value is the sum of the two before it}}{a_n=a_{n-2}+a_{n-1}} \\\\\\ ~\hspace{34em}

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Describe how making a list can help you solve a math problem.
Margarita [4]
Making a list can help you solve a problem by:
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those are some of the basic ways,
8 0
3 years ago
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Hey -
Katen [24]

Answer:

4-3=1

8+9=17

7 x 2= 14

Step-by-step explanation:

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How can you use the multiplication property of equality to rewrite the equation 0.6x + 4.8 = 7.2
Kobotan [32]
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Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
What the answer is ?
fgiga [73]

Answer:

A. 5 + 2.75 · S ≤ 21

Step-by-step explanation:

So we know that it has to be less than or equal to $21 because that's all she has to spend. So we can automatically rule out the equations with ≥  because that means greater than.

We can also rule out the equations that have 50 at the very end because that's just how far she wants to travel.

4 0
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