Find a recursive rule for the sequence 2 4 6 10

1 answer:

7 0

$\bf 2~~,~~4~~,~~\stackrel{2+4}{6}~~,~~\stackrel{4+6}{10} ~\hfill \stackrel{n^{th}\textit{ value is the sum of the two before it}}{a_n=a_{n-2}+a_{n-1}} \\\\\\ ~\hspace{34em}$

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What is 25/6 with remainder

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Use the equation below to answer the following questions.

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the answer is

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Ahat [919]

Answer:

The angle is "27 and 63".

Step-by-step explanation:

Let A and B are two angles, in which A is " $\frac{1}{2}$ " complementary angles and B be is another complementary angle.

Condition of complementary angle :

$A+B =90 ......(i)$

Solution:

$\ A = \ 3B - 18 \\\\ \ put \ the \ value \ of \ A \ in \ equation.....(i) \\\\ \ Equation: \\ \\\Rightarrow \ A\ +\ B \ =\ 90 \\\\\Rightarrow \ 3B\ -\ 18 \ + \ B \ = \ 90 \\\\\Rightarrow \ 4B \ = \ 90 +18 \\\\\Rightarrow \ 4B = 108 \\\\ \Rightarrow B = \frac{108}{4} \\\\ \Rightarrow B \ = \ 27\\$

$\ put \ the \ value \ of \ B \ in \ equation (i).\\\\ \ Equation: \\\\\Rightarrow A+B=90\\\\\Rightarrow A+27=90\\\\\Rightarrow A=90-27\\\\\Rightarrow A= 63$