Part (a)
P(A) = 0.5
P(B) = 0.4
P(B/A) = 0.6
P(A and B) = P(A)*P(B/A)
P(A and B) = 0.5*0.6
P(A and B) = 0.3
<h3>Answer: 0.3</h3>
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Part (b)
We'll use the result from part (a)
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.5 + 0.4 - 0.3
P(A or B) = 0.6
<h3>Answer: 0.6</h3>
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Part (c)
A and B are not independent since P(B) does not equal P(B/A). The fact that event A happens changes the probability P(B). Recall that P(B/A) means "probability P(B) based on event A already happened". A and B are independent if P(B) = P(B/A).
Events A and B are not mutually exclusive since P(A or B) is not zero.
<h3>Answer: Neither</h3>
Answer:
0.1725
Step-by-step explanation:
17 1/4 /100
17.25/100
0.1725
Use the conditional probability formula, P(a|b) = P(a and b)/P(b)
Answer:
21
Step-by-step explanation:
since its a rectangle there are two lengths of six. If you add them together you get 12. subtract the total perimeter of 54 by the 12 and get 42. Since there is 2 sides left divide by 2. You should get 21 for the width of the rectangle
This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.
a = -3
b = -4
c = -4
x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) =
<em>2 + √-32/2</em>x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =
<em> 2 - √-32/2</em>
