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3 years ago

Which of the following systems of linear equations has no solution?

Mathematics

2 answers:

madreJ [45]3 years ago

5 0

None of them above the last one

marusya05 [52]3 years ago

5 0

Answer:

D. none of the above

Step-by-step explanation:

They all have at least one solution.

I hope this helps :)

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PLEASE HELP FOR A BRAINLIEST!!!! Create your own example and explain how to solve Quadratic Equation using Quadratic Formula. Wh

SVETLANKA909090 [29]

Step-by-step explanation:

1. Create your own example and explain how to solve Quadratic Equation using Quadratic Formula.

The quadratic formula is used to solve quadratic equations. It is shown as $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

A quadratic equation is generally shown in the form of $ax^{2} +bx + c = 0$

For example, if you saw the equation $7x^{2} + 3x + 20 = 0$

7 would be $a$ , 3 would be $b$ , and 20 would be $c$ .

To solve the equation above, you would fill in the quadratic formula as such, $x=\dfrac{-3\pm\sqrt{(3)^2-4(7)(20)}}{2(7)}$

Then you could solve for x.

2. What part in the Quadratic Formula is the discriminant?

The discriminant is the equation under the square root on the quadratic formula, $b^{2} - 4ac$

It is tells us whether there are two solutions, one solutions, or no solutions.

3. How do you know the number of solutions based on the value of the discriminant?

To know the number of solutions based off of the value of the discriminant, you need to plug in your values. Using the example quadratic equation, $7x^{2} + 3x + 20 = 0$

We will plug the values into the discriminant.

$3^{2} - 4(7)(20) = -551$

Now, if the discriminant is positive it has two real solutions. If the discriminant is zero the equation has no real-number solutions. And finally, if the discriminant is negative, the equation has one real solution. Because our discriminant is -551, the example equation has one real solution.

Hope this helps! (Please consider Brainliest)

8 0

3 years ago

A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s

Artemon [7]

Answer:

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

$x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 0 \ \leq age \leq 2 }\\{0 \ \leq age \leq 3}\end{array}\right]$

Also , the age transition matrix is as follows:

$L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]$

After 1 year ; the age distribution vector will be :

$x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right] \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]$

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$