If it takes Matthew an hour to get to his friends house, and two hours if he drives 25 mph slower, how far away does Matthews fr
iend live?
2 answers:
Speed = distance/time
distance = speed * time
d = st
Let distance = d; faster speed = s; t = time
At the faster speed:
d = s * t
d = s * 1
d = s
At the slower speed:
d = st
d = (s - 25)* 2
d = 2s - 50
We now have two equations,
d = s
d = 2s - 50
We can equate the right sides
s = 2s - 50
-s = -50
s = 50
The faster speed is 50 mph.
It takes him 1 hour at the faster speed.
d = st
d = 50 mph * 1 hr
d = 50 miles
Answer: the distance is 50 miles
50 miles gggggggggggggggggtffgfffffgfggfff
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Step-by-step explanation:
Tn=ar^(n-1)
r=-10/-5=2
a=-5
Tn=-5×(2)^(n-1)
Tn=-5•(2)^(n-1)
an=5•(2)^(n-1)
Answer: i think
the corrcect answer is 0.5*10^-1
Step-by-step explanation:
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X= -2 or X= 3 either one works.
X=6y
sum of their reciprocals
(1/x)+(1/y)=7
x=6y
1/6y+1/y=7
1/6y+6/6y=7
7/6y=7
times both sides by 6y
7=42y
divide both sides by 42
1/6=y
x=6y
x=6(1/6)
x=6/6
x=1
the numbers are 1 and 1/6