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Bess [88]
3 years ago
14

It has a diameter of 2 inches what is the radius

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
Radius is the half of diameter.
That means the radius is 2inch/2=1inch.

Good luck mate!
Norma-Jean [14]3 years ago
7 0
It’s half the diameter which is 1 inch
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If you bought a stock last year for a price of 103$ and it has risen 13.5% since then, how much is the stock worth now, to the n
DIA [1.3K]

Answer:

$90.75

Step-by-step explanation:

103*100=(13.5%+100%)*x

10300=113.5x

x=10300/113.5

x=90.74889868

x=$90.75

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3 years ago
The mass of a solid cube with side length of 2 cm is 12 g. Which is the closest to the density of the cube? Show your work. A)0.
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D = m/v
V = 2•2•2 = 8cm^3
D = 12/8 = 1.5g/cm^3

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3 0
3 years ago
Zara's weekly pay is increased by 5% to $315. What was Zara's pay before the increase
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$299.25

Step-by-step explanation:

What is 5% of $315? = $15.75

Therefore $315 - 5% =

$315 - $15.75

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2 years ago
Please help me! The area of the triangle is 48 square centimeters. What is the height of the triangle in centimeters
nevsk [136]
You have to put 17cm on the other side and then multiply to get the answer
8 0
3 years ago
A container holds 50 electronic components, of which 10 are defective. if 6 components are drawn at random from the container, t
love history [14]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1</u>

We know that there's a probability of p=\frac{40}{50}=\frac{4}{5}=0.8 of choosing an electronic component that is not defective and a probability of q=\frac{10}{50}=\frac{1}{5}=0.2 of choosing an electronic component that is defective:

\displaystyle P(X\geq4)=P(X=4)+P(X=5)+P(X=6)\\\\P(X\geq4)=\binom{6}{4}(0.8)^4(1-0.8)^{6-4}+\binom{6}{5}(0.8)^5(1-0.8)^{6-5}+\binom{6}{6}(0.8)^6(1-0.8)^{6-6}\\\\P(X\geq4)=\frac{6!}{4!(6-4)!}(0.8)^4(0.2)^2+\frac{6!}{5!(6-5)!}(0.8)^5(0.2)^1+\frac{6!}{6!(6-6)!}(0.8)^6(0.2)^0\\ \\P(X\geq4)=0.90112

So, if 6 components are drawn at random from the container, the probability that at least 4 are not defective is 0.90112

<u>Problem 2</u>

<u />\displaystyle P(X=3)=\binom{8}{3}(0.2)^3(1-0.2)^{8-3}\\\\P(X=3)=\frac{8!}{3!(8-3)!}(0.2)^3(0.8)^5\\ \\P(X=3)\approx0.1468

So, if 8 components are drawn at random from the container, the probability that exactly 3 are defective is 0.1468

6 0
2 years ago
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