Answer:
solution given:
B.
CE=2×2=4[base side is double to the line of mid point]
AB=15/2=7.5[b is a mid point]
m<AEC=75°[ corresponding angle]
5.
given:
BD=x+1
CE=x+10
we have
2BD=CE
2(x+1)=x+10
2x+2=x+10
2x-x=10-2
x=8
Step-by-step explanation:
In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)
2.5(6-x) = 0
Open the bracket,
(2.5×6)-2.5x= 0
Collect like terms.
2.5x= 2.5×6
Divide both sides by the coefficient of x (2.5)
x = 6
So,
x= 6 is true.
.
Substituting 6 for x in the equation,
2.5(6-6)= 0
2.5•0 = 0
0= 0
Which is also true.
Answer: 20
Step-by-step explanation:
x+y=5
x-y=4
---------
x+y=5
x=4+y
--------
(4+y)+y=5
4+y+y=5
4+2y=5
2y=1
y=0.5
x=4.5
---------
x²-y²=(4.5)²-(0.5)²=20.25-0.25=20
To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3
Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3
Then you can divide 273 by 3 to get the final answer:
273/3 = 91
He will have 91 peaches overall.
Hope this helps! :)
