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Luda [366]
3 years ago
8

What is the common ratio of the following sequence?80, 20,5A. -4B. 1/4C. 4​

Mathematics
1 answer:
Inga [223]3 years ago
3 0

Answer:

(C.) 4

Step-by-step explanation:

80÷4=20

20÷4=5

Each number is divided four.

So four is the common ratio.

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Michael sold 2 flowers in 4 hours, 3 flowers in 6 hours, 4 flowers in 8 hours, and 5 flowers in 10 hours. Which statement correc
Tom [10]

Answer:

D

Step-by-step explanation:

Sorry if the answer is late

5 0
3 years ago
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Solve this systems of equation word problem. please
agasfer [191]
2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
2b + 4h = 7.40
subtract the first equation from it:
3h = 2.58
h = 0.86
5 0
3 years ago
If the point (x, y) is on the y-axis, which of the following must be true? A). x=0 B). y=0
Musya8 [376]

Answer:

X = 0

Step-by-step explanation:

3 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
Find the area of following figure...?​
MrRa [10]

Answer:

33600 m²

Step-by-step explanation:

The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

DE + EC = DC

EC = AB = 360 m

DC = 600 m

DE + 360 m = 600 m

DE = 240 m

Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

DE² + 240² = 250²

DE² = 62500 - 57600

DE² = 4900

DE = √4900

DE = 70

BC = 70 = h

area = (a + b)h/2

area = (600 m + 360 m)(70 m)/2

area = 33600 m²

4 0
2 years ago
Read 2 more answers
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