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3 years ago

6

Use the Polygon tool to draw the image of the given quadrilateral under a dilation with a scale factor of 34 and center of dilat

ion (0, 0) .

1 answer:

Margarita [4]3 years ago

4 0

Answer:

See attached diagram

Step-by-step explanation:

Given quadrilateral has vertices at points A(-8,4), B(4,-4), C(0,-8) and D(-4,-4).

A dilation with a scale factor of $\dfrac{3}{4}$ and a center of dilation (0,0) has a rule

$(x,y)\mapsto \left(\dfrac{3}{4}x,\dfrac{3}{4}y\right).$

Then

A(-8,4)→E(-6,3);
B(4,-4)→F(3,-3);
C(0,-8)→G(0,-6);
D(-4,-4)→H(-3,-3).

See attached diagram for details.

Remark: If a scale factor is 34, then the rule is (x,y)→(34x,34y) and image vertices have coordinates (-272,136), (136,-136), (0,-272), (-136,-136).

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MArishka [77]

Answer:

Step-by-step explanation:

When two variables say x and y are proportional let us assume y dependent variable and x independent variable

then we have y =kx

Here k is called the constant of proportionality.

Whenever x increases/decreases by 1 unit, the y value also increases/decreases by k units.

Whenever x=1, y =k

and always $\frac{y}{x} =k$

Thus we can fill up as

the constant of proportionality is always the point___(1.k)____, where k is the constant of proportionality. Additionally, you can find the constant of proportionality by finding the ratio of___y to x____, for any point on the___graph of the function.___.

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3 years ago

What is the solution of the equation over the complex numbers

denis-greek [22]

<u>Answer:</u>

$2i\sqrt{3}$

$-2i\sqrt{3}$

<u>Step-by-step explanation:</u>

$x^2 + 12$

First set the equation to 0

$x^2 + 12$

$x^2 + 12 = 0$

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

$x^2 + 12 = 0$

$x^2 + 12 + (-12) = 0 -12$

$x^2 = -12$

Square root both sides of the equal sign.

$x^2 = -12$

$\sqrt{x^2} = \sqrt{-12}$

Take the square root on left sides of the equal sign.

$\sqrt{x^2} = \sqrt{-12}$

$x = \sqrt{-12}$

Take the square root on the right side of the equal sign. Remember $\sqrt{-1} = i$

$x = \sqrt{-12}$

$x = \sqrt{4}*\sqrt{-1}\sqrt{3}}$

$x = 2i\sqrt{3}$

<u>AND</u>

$x = -2i\sqrt{3}$

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3 years ago

Evaluate 2LW + 2HL + 2HW for L = 3,W = 2, and H = 4. 48 46

JulijaS [17]

2(3)(2) + 2(4)(3) + 2(4)(2)

2(6) + 2(12) + 2(8)

12 + 24 + 16

52

Hope this helps!

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3 years ago

Read 2 more answers

PLEASE HELP! WILL GIVE BRAINLIEST!

Alex Ar [27]

The one in the middle you can tell because when x=0 that is the y intercept and the graph had a y intercept of 4 and the middle graph had 5

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3 years ago

Read 2 more answers

Amy and Ben share £21 between them in the ratio 5 : 2. How much does Amy get?

Alika [10]

Answer:

✑ $\underline{ \underline{ \sf{First ,\: Let's \: learn \: about \: the \: ratio}}} :$

Let us consider , there are 30 boys and 40 girls in a school. So, the ratio of number of boys to number of girls = $\sf{ \frac{30}{40} = \frac{3}{4} = 3:4}$ and read as 3 is to 4. We can say , the ratio compares two of more quantities of same unit. Until two quantities have same units , it is meaningless to compare by ratio. So, to find the ratio of two quantities , it is necessary to express them in same unit or of same kind. Since , they are in division form. So ,ratio is unit less quantity. Thus , the ratio is a comparison of two quantities of the same kind in division which doesn't have any units. For example : $\sf{ \frac{a}{b}}$ is a ratio and is read as ' a is to b ' in which ' a : is antecedent and ' b ' is called consequent.

✎ $\underline{ \underline{ \sf{Now \: let's \: solve : }}}$

☪ $\underline{ \sf{Solution}} :$

£ 21 is to be divided between Amy and Ben in the ratio 5 : 2. So, let Amy get £ 5x and Ben get £ 2x.

Then , According to the question , $\text{5x +2x = 21}$

Solve for x :

⇝ $\sf{7x = 21}$

⇝ $\sf{ \frac{7x}{7} = \frac{21}{7} }$

⇝ $\sf{x = 3}$

The value of x is 3. Now , substitute the value of x in 5x :

Amy received £ 5x = 5 × 3 = £ 15 .

☥ $\boxed{ \boxed{ \tt{Our \: final \: answer \: is \bold{£ \: 15}}}}$

Hope I helped ! ツ

Have a wonderful day / night ♡

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6 0

2 years ago