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3 years ago

Find the quotient: 13 ÷ 5/11 pls help ASAP

Mathematics

2 answers:

dezoksy [38]3 years ago

8 0

Answer:

143/5

28 3/5

Step-by-step explanation:

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gladu [14]3 years ago

5 0

Answer:

143/5, 28.6, or 28 3/5

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Hellppp 70 pointsss

dimulka [17.4K]

y=a.(X-x1)(X-x2)

x1 and x2 are x-intercepts

x1=-3

x2=1

other points: (-1,8) and (0,5)

y=a.(x+3).(x-1)

a=-2

f(x)= -2.(x+3)(x-1)

7 0

3 years ago

Find an equation of the plane with the given characteristics. The plane passes through the points (4, 3, 1) and (4, 1, -7) and i

Minchanka [31]

Answer:

$3x - 4y + z = 1$

Step-by-step explanation:

Given

$Point\ 1 = (4,3,1)$

$Point\ 2 = (4,1,-7)$

Perpendicular to $8x + 7y + 4z = 18$

Required

Determine the plane equation

The general equation of a plane is:

$a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

For $n =$

$(x_1,y_1,z_1) = (4,3,1)$

$(x_2,y_2,z_2) = (4,1,-7)$

First, we need to determine parallel vector $V_1$

$V_1 =$

$V_1$ is parallel to the required plane

From the question, the required plane is perpendicular to $8x + 7y + 4z = 18$

Next, we determine vector $V_2$

$V_2 =$

This implies that the required plane is parallel to $V_2$

Hence: $V_1$ and $V_2$ are parallel.

So, we can calculate the cross product $V_1 * V_2$

$V_1 =$

$V_2 =$

$n = V_1 * V_2$

$V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]$

The product is always of the form + - +

So:

$V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]$ $-j\left[\begin{array}{cc}0&8\\8&4\end{array}\right]$ $+k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]$

Calculate the product

$V_1 * V_2 = i(2*4- 8*7) - j(0*4- 8*8) + k(0*7 - 2 * 8)$

$V_1 * V_2 = i(8- 56) - j(0- 64) + k(0 - 16)$

$V_1 * V_2 = i(-48) - j(- 64) + k(- 16)$

$V_1 * V_2 = -48i +64j - 16k$

So, the resulting vector, n is:

$n =$

Recall that:

$n =$

By comparison:

$a = -48$ $b = 64$ $c = -16$

Substitute these values in $a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

$-48(x-x_1) + 64(y - y_1) -16(z-z_1) =0$

Recall that: $(x_1,y_1,z_1) = (4,3,1)$

So, we have:

$-48(x-4) + 64(y - 3) -16(z-1) =0$

$-48x + 192 + 64y -192 - 16z +16 = 0$

Collect Like Terms

$-48x + 64y - 16z = 0 - 192 + 192 - 16$

$-48x + 64y - 16z = -16$

Divide through by -16

$3x - 4y + z = 1$

Hence, the equation of the plane is $3x - 4y + z = 1$

4 0

3 years ago

COMPLETING THE SQUARE 2x^2 -4x+3=9 2. QUADRATIC FORMULA 2x^2+4x=0

jek_recluse [69]

X = 3 and x = -1 are the answers for both. They are exactly the same equation.

FOR COMPLETING THE SQUARE
Make in terms of ()^2 which you can do by adding numbers to both sides. Eventually it will look like this:
(2x - 1)^2 - 7 = 0
Add to both sides, take a square root and then solve.

USE THE QUADRATIC FORMULA
Be sure to solve for zero and be aware of negatives when plugging in.

3 0

3 years ago

Primo car rental agency charges $24 per day plus $0.40 per mile. Ultimo car rental agency charges $38 per day plus $0.90 per

aalyn [17]

Answer:

when the distance driven per day is 100 miles

Step-by-step explanation:

Start by writing an equation for the daily charge of each company

Let's call p(x) what the primo car rental charges per mile "x", and let's call u(x) what ultimo rental charges;

p(x) = 24 + 0.4 x

u(x) = 38 + 0.9 x

when would u(x) be twice the p(x) charge?

u(x) = 2 p(x)

38 + 0.9 x = 48 + 0.8 x

0.9 x - 0.8 x = 48 - 38

0.1 x = 10

x = 100

so, such happens when the distance driven per day is 100 miles

6 0

4 years ago

If a cross section was cut that was parallel to the base of a triangular prism below a shape with that cross section be ?

velikii [3]

The answer is A) square

6 0

3 years ago

Read 2 more answers