A.
y = 15 tan(30°)
y = 15/√3 ≈ 8.66 ft
b.
y = 15 tan(40°) ≈ 12.59 ft
c.
A = 1/2 base x height ≈ 129.9 ft² and 188.8 ft² for 30° and 40°
hope it helps
I think that 0.45 would be one.
Point A is the midpoint of CT which means the ratio of CA:CT would be 1:2.
To find CT, you need to find the distance of CA then applies 2 times of the distance to the point C
Xca= Xa-Xc= 1- (-2)= 3
Yca= Ya- Yc= -3 -5= -8
Xt= Xc + 2* Xca= -2 + 2*3= 4
Yt= Yc + 2* Yca= 5 + 2*-8= -11
T(Xt, Yt)= T(4, -11)
The coordinate for point T would be (4, -11)
Answer:
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