We know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
<span>common ration r is equal to 3
number of terms n is 12
The </span><span>Sum of geometric series is given by the formula
</span>Sum=a1*[1-r<span>^n]/[1-r]
</span>Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
<span>Sum=531440/2-----> 265720
the answer is
265720
</span>
Answer:
Hi , your answer is V = 4/3 πr³.
Hope this helps
Answer:
Look in the file, I've drew it there!
<span>First we calculate z using the formula:
z = (x - μ)/σ</span>
Where:
x = our variable, 10
μ = mean, 8
σ = standard dev, 2
Substituting known
values:<span>
z = (10 - 8)/2
z = 2/2
z = 1
Using the tables of
the normal distribution to find the p-value with z = 1
p = 0.8413
Since we want
"greater than 10”, we need to subtract the probability from 1
therefore
p* = 1 - 0.8413 = <span>0.1587</span></span>