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slavikrds [6]
4 years ago
13

Very urgent answer required! What is the total number of liters of water Chelsea used over these 4 days?

Mathematics
1 answer:
kicyunya [14]4 years ago
3 0
From the graph we can tell that the numbers of liters are 7.5, 7.5, 8.6, and 9.3
add them up, the total is 32.9 
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Find the midpoint of the line segment whose endpoints are given (3/5 , -6/7),(2/5,5/7)
snow_lady [41]

The formula of a midpoint between E and F:

M_{EF}\left(\dfrac{x_E+x_F}{2};\ \dfrac{y_E+y_F}{2}\right)

We have the points \left(\dfrac{3}{5},\ -\dfrac{6}{7}\right) and \left(\dfrac{2}{5},\ \dfrac{5}{7}\right). Substitute:

\dfrac{\frac{3}{5}+\frac{2}{5}}{2}=\dfrac{\frac{5}{5}}{2}=\dfrac{1}{2}\\\\\dfrac{-\frac{6}{7}+\frac{5}{7}}{2}=\dfrac{-\frac{1}{7}}{2}=-\dfrac{1}{7}\cdot\dfrac{1}{2}=-\dfrac{1}{14}

Answer: \boxed{\left(\dfrac{1}{2},\ -\dfrac{1}{14}\right)}

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3 years ago
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6%
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8 0
4 years ago
The rates of currency exchange published in the newspaper on a certain day showed that 12 pounds could be exchanged for 96 dolla
stealth61 [152]

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Step-by-step explanation:

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7 0
3 years ago
The measurement of the radius of the end of a log is found to be 9 inches, with a possible error of 1/2 inch. Use differentials
enot [183]

Answer:

\pm 9in^2

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, \Delta r=\pm 1/2in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A=pi r^2

\frac{dA}{dr}=2\pi r

\frac{dA}{dr}=2\pi (9)=18\pi in^2

Now,

Approximate error in area

dA=\frac{dA}{dr}(\Delta r)

Using the values

dA=18\pi (\pm 1/2)

\Delta A\approx dA=\pm 9in^2

Hence, the possible propagated error in computing the area of the end of the log=\pm 9in^2

6 0
3 years ago
Read 2 more answers
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