Please help me. This is so confusing.

2 answers:

6 0

<span>
The vertices of a polygon are given as follows: P(-2,4), Q(4,2), R(4,0); S(-12,0); k = 0.5 Find the coordinates of the vertex P' of the image after a dilation having the given scale factor. Type your answers as a coordinate pair in this format: (x,y)</span>

Mumz [18]3 years ago

3 0

If the center of dilation is the origin, you can just multiply each coordinate by the scale factor to find the new values.

P' will be (-1, 2)

If the center of dilation isn't the origin, my answer is invalid.

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Please help ty so much

kobusy [5.1K]

M=(14-7)/(10-5)=7/5.

7 0

3 years ago

How do i solve 12×+9=10×1

s2008m [1.1K]

Answer:

Step-by-step explanation:

Unfortunately, your " 12×+9=10×1 " can be interpreted in more than one way. The symbol " × " should be used ONLY to indicate multiplication. Thus, " 12× " reads as ' 12x.' Then we have: 12x + 9 = 10. Unsure of what you meant by " 10×1". So I will treat your "10×1" as simply '10.'

Then we have 12x + 9 = 10, which reduces to 12x = 1 if we subtract 9 from both sides.

12x = 1 yields x = 1/12.

If this is not the result you expected, please go back to the original problem and share it as accurately as you can.

6 0

3 years ago

32) (a)-(c) pre calculus

Harrizon [31]

Well, remember we can't take the square root of a negative

so we see that we have $\sqrt{1-x^2}$
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain

b. for a TI-84, go to y-editor then input $4x \sqrt{1-x^2}$ for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7

A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7

8 0

3 years ago

Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided

scoray [572]

Let me express the equation clearly:

lim x→-9 (x²-81)/(x+9)

Initially, we solve this by substituting x=-9 to the equation.

((-9)²-81)/(-9+9) = 0/0

The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.

(2x-0)/(1+0) = 2x = 2(-9) = -18

The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999

((-8.999)²-81)/(-8.999+9) = -18

7 0

3 years ago

Tony had an equal number of cranberry bars and walnut bars. He gave away 66 cranberry bars, he then had 4 times as many walnut b

Korolek [52]

Answer:

W=88

Step-by-step explanation:

4*(c-66)=c

4c-66*4=c

3c=66*4

c=22*4

c=88

w=88

4 0

2 years ago

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