Exponential laws

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)=
![\sqrt[3]{m^{1}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B1%7D%7D%20)
=
Answer:
1st option
Step-by-step explanation:
given the graph of f(x) then the graph of f(x) ± c is a vertical translation of f(x)
• if - c then a shift down of c units
• if + c then a shift up of c units
then for f(x) + 4 is a shift up of 4 units
The equation is equivalent to 1/cos(2x)-2=sin(2x)/cos(2x). Make the denominator cos(2x) for all terms, we get 1-2cos(2x)=sin(2x). Since cos^2(2x)+sin^2(2x)=1, let cos(2x)=a, substitute sin(2x) by +-\sqrt(1-a^2), and solve the equation with only one variable a. We get a=4/5 or 0, but cos(2x) cannot be 0, otherwise sec(2x) is undefined. 2x=36.9 degrees, so x=18.9 degrees approximately.