one piece of ash was ejected from the volcano with the velocity of 368ft/sec. The height H, in feet of our ash projectile is giv
en by the equation. when does the ash projectile reach maximum height? what is its maximum height? when does the ash projecticle return to the ground? H=16t^2+368
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Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they need to have the same slope.
To find the slope (m), use the slope formula:
And plug in the two points
(-2, 7) = (x₁, y₁)
(4, -5) = (x₂, y₂)
(two negative signs cancel each other out and become positive)
Simplify the fraction
m = -2
The slope is -2, so the parallel line's slope is also -2.
Your answer is C